sedgewick algorithms

1 Packagealgorithms.fundamentals001;2 3 ImportJava.util.Locale;4 ImportJava.util.Scanner;5 6 Importalgorithms.util.StdIn;7 8 Public classIsequals {9 Ten //assume Unicode UTF-8 encoding One Private Static FinalString charset_name = "UTF-8"; A - //Assume language = 中文版, country = US for consistency with System.out. - Private Static FinalLocale locale =locale.us; the - Private StaticScanner Scanner; - //Do the once when StdIn is initialized - Static { + Resync ()

("-") | | +S.equals ("*") | | AS.equals ("/") | | theS.equals ("sqrt")) + { - Doublev =Vals.pop (); $ $ if(S.equals ("+")) v = vals.pop () +v; - Else if(S.equals ("-")) v = vals.pop ()-v; - Else if(S.equals ("*")) v = vals.pop () *v; the Else if(S.equals ("/")) v = vals.pop ()/v; - Else if(S.equals ("sqrt")) v =math.sqrt (v);Wuyi the Vals.push (v); -

(s)); - Continue; $ } the the //Token is an operator the while(true) { the - //The last condition ensures, the operator with higher precedence is evaluated first in if(Ops.isempty () | | s.equals ("(") | | (Precedence.get (s) >Precedence.get (Ops.peek ()))) { the Ops.push (s); the Break; About } the the //Evaluate Expression theString op =Ops.pop (); + -

polygon.There should be no intersection between the parent of the recursive call and the child problem that is trying to resolve. In the following code, two sub-issues areThe array part of the self-operation is different.1 Public Static intRankintKeyint[] A,intLointhi) { 2 //if key exists in a[], its index will not be less than lo and will not be greater than hi3 if(Lo > Hi)return-1;4 intMid = lo + (Hi-lo)/2;5 if(Key returnRank (key, A, lo, mid-1);6 Else if(Key > A[mid])ret

intHi =Lo; + for(intj = 1; J ) { - while(!queues[j].isempty () Queues[j].peek () hi) { the queues[j].dequeue (); * } $ if(Queues[j].isempty ()) {Panax NotoginsengDone =true; - Break; the } + ElseHi =Queues[j].peek (); A } the if(!done Hi-lo Bestlo) { +Besthi =Hi; -Bestlo =Lo; $ } $ - } - the if(Bestlo >= 0) { -

1 /*************************************************************************2 * 3 * Josephus Problem4 * 5 *% java ex_1_3_37 7 26 * 1 3 5 0 4 2 67 * 8 *************************************************************************/9 Ten Public classex_1_3_37 One { A Public Static voidMain (string[] args) - { - intn = integer.parseint (args[0]), them = Integer.parseint (args[1]); - -queueNewQueue(); - for(inti = 0; I ) +Q.enqueue (NewInteger (i)); - +

the items on the ' queue ' in FIFO order.98 */ About PublicIteratoriterator () { - return NewListiterator (); 101 }102 103 Private classListiteratorImplementsIterator {104 Private intn =N; the PrivateNode current =Last ;106 107 Public BooleanHasnext () {returnn > 0; }108 Public voidRemove () {Throw Newunsupportedoperationexception (); }109 the PublicItem Next () {111 if(!hasnext ())Throw Newnosuchelementexception

expression known as a postfix expression. the * 1 2 3 + 4 5 * * + + * A * the ******************************************************************************/ + - Public classEvaluate { $ Public Static voidMain (string[] args) { $stackNewStack(); -StackNewStack(); - the while(!Stdin.isempty ()) { -String s =stdin.readstring ();Wuyi if(S.equals ("(")) ; the Else if(S.equals ("+") ) Ops.push (s); - Else if(S.equals ("-") ) Ops.

- //Return the number of items in the queue. the Public intsize () { + returnStack1.size () +stack2.size (); A } the + //return the item least recently added to the queue. - PublicItem Peek () { $ if(IsEmpty ())Throw NewNosuchelementexception ("Queue underflow"); $ if(Stack2.isempty ()) Movestack1tostack2 (); - returnStack2.peek (); - } the - //Add the item to the queueWuyi Public voidEnqueue (item item) { the Stack1.push (i

1 PackageAlgorithms.util;2 3 /******************************************************************************4 * Compilation:javac Directory.java5 * Execution:java Directory directory-name6 * Dependencies:Queue.java Stdout.java7 * 8 * Prints out all of the files in the given directory and any9 * subdirectories in Level-order by using a queue. Also PrintsTen * out their file sizes in bytes. One * A *% java Directory. - * - *********************************************************************

Update: July 4, 2014 Chap 5: At the beginning, he mentioned that: recursion is a divide-and-conquer method. although extends algorithms can be solved in simple recursion but it is often an equally algorithm lies in the details of a nonrecursive implementation? (Not understood) Divide-and-conquer programs normally do not reduce to trivial loops since they have 2 recursive cballs and do had divided without overlap so no excessive recomputing. /** me