The general program idea is to use the recursion to calculate how much space the directory occupies, and then the space to occupy the value of the text file, so long as the access to this TXT file to know how much space occupied, do not have frequent access to read disk, save resources. Each time a user uploads a file or deletes a file, it is then counted again. Of course, you can also save the results to the database.
Copy
The rmdir () function deletes an empty directory.
Cases
The code is as follows
Copy Code
$path = "Images";if (!rmdir ($path)){Echo ("Could not remove $path");}Else{Echo ' Delete directory failed because images is not empty directory ';}?>
directory under new. htaccess below is the code. See for yourself!
The code is as follows
Copy Code
Rewriteengine onRewritebase/Redirect Permanent/Your directory address http://www.111cn.net
Of course, it can be written directly in the
A level Two directory is often encountered in development projects. For example, the article module, product modules, many should be based on the two-level classification form. and the ordinary solution to sort the scheme, whether it is a level classification, or multi-level classification, are by the administrator in the background manually edit the peer category sorting values to set the order, based on the size of the value of the decision to displ
Due to my side of the network reasons, no use from the official website of FCK download to the source code ...
This set of source code is FCK2.2 version of the reverse compiled
Source: Click here to download the main changes in the source to do the comments
The general changes are as follows:
Get the source of the user directory: FileWorkerBase.cs
Here's a f
JSP tutorial shows all files and subdirectory code under the directory
public static void GetFiles (listFile File = new file (path);
file[] files = file.listfiles ();
if (files = null) {
Return
} else {
for (int i = 0; i Determine if it is a folder
if (Files[i].isdirectory ()) {
Recursive call GetFiles method to get all the files
GetFiles (FileList, Getavailablepath (files[i)), filesuffix);
else
Copy Code code as follows:
"" "This module contains the code from
The I-Am Python by Allen B. Downey
Http://thinkpython.com
Copyright Downey Allen B.License:gnu GPLv3 http://www.gnu.org/licenses/gpl.html
"""
Import OS
def walk (dirname):"" "finds the names of all files in DirName and its subdirectories.
dirname:string Name of
"The total directory of Bowen >>>"
Leetcode algorithm title
Leetcode is a very useful site to prepare for the interview, is very worthwhile to go to the place, which are some of the classic face questions, these topics in the Google,microsoft,facebook,yahoo and other large Internet companies interview questions have appeared, and the topic is divided into easy, Difficult third, but also according to the topic of classification, when the problem can
(Findfiledata.dwfileattributes File_attribute_directory){is not the current directory, nor is it a parent directoryif (findfiledata.cfilename[0]!= '. '){Find Next Level directory_find (prefix+findfiledata.cfilename+ "//" + "* *");}}fileElse{cout}if (! FindNextFile (Hfind,findfiledata))Break}FindClose (hfind);}void Main () {Find ("E:");// directory:E - Drive_find ("E://*.*");//e all files under diskString str= "./test"; The
VBS gets the names of all folders under the current directory, excluding subfolders. I want to work with each folder, so it's best to use the loop output.
When testing to ensure that there is a folder in the current directory can be, otherwise the output is empty.
Copy Code code as follows:
Set ws=wscript.
This article is the PHP traverse a directory of all files and subfolders of the implementation code for a detailed analysis of the introduction, the need for friends to
copy the Code code below:
function Read_all_dir ($dir){$result = Array ();$handle = Opendir ($dir);if ($handle){while (($file = Readdir ($handle))!==
The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion;
products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the
content of the page makes you feel confusing, please write us an email, we will handle the problem
within 5 days after receiving your email.
If you find any instances of plagiarism from the community, please send an email to:
info-contact@alibabacloud.com
and provide relevant evidence. A staff member will contact you within 5 working days.