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+1+x[x[k].s[1]].zs; X[k].z= (x[x[k].s[0]].z*cf[x[x[k].s[1]].zs+1]%p+x[k].c*cf[x[x[k].s[1]].zs]%p+x[x[k].s[1]].Z)%p;}voidChanintKintACharZF) { if(x[x[k].s[0]].zs>=a) Chan (x[k].s[0],A,ZF); Else if(x[x[k].s[0]].zs+1==a) x[k].c=ZF; ElseChan (x[k].s[1],a-x[x[k].s[0]].zs-1, ZF); Pu (k);}voidXzintAintk) { intb=x[a].fa,bb=x[b].s[1]==a,cc=x[x[b].fa].s[1]==b; if(k==b) k=A; Elsex[x[b].fa].s[cc]=A; X[A].FA=X[b].fa; X[X[B].S[BB]=x[a].s[!bb]].fa=b; x[x[a].s[!bb]=b].fa=A; PU (b);}voidSplay (int K,inta)

)-(1202 CPUs + 176 GPUs with 40 search threads)There is a Twitter user mapping:From this point of view, it is understandable that Korean protests against Li Shishi are unfair to the people.The algorithm structure of AlphagoThis article tries to use the simplest method to tell the Alphago algorithm, and to understand how Alphago plays chess.Alphago's technical overall architecture if one sentence is summed up: The deep CNN Neural network Architecture combines the Monte Carlo search tree (Monte Ca

(radLat2) * Math. pow (Math. sin (B/2), 2 )));S = s * EARTH_RADIUS;S = Math. round (s * 10000)/10000.0;Return s;} This formula is correct in most cases. problems may occur only when dealing with relative points on the sphere,There is a formula for correction.Because there is no need, you can find it on the wiki.Of course, we all know that the earth is not a real sphere, but an elliptical sphere, so we have the following formula:Copy codeThe Code is as follows:/*** Approx distance between two po

and using arraylist that is not automatically sorted as the intermediate bridge using System; Using System. Collections; Namespace NoSortHashtable{Public class NoSortHashtable: Hashtable{Private ArrayList keys = new ArrayList (); Public NoSortHashtable (){} Public override void Add (object key, object value){Base. Add (key, value );Keys. Add (key );} Public override ICollection Keys{Get{Return keys;}} Public override void Clear (){Base. Clear ();Keys. Clear ();} Public override void Remove (ob

) *math.cos (RADLAT2) *math.pow (Math.sin (b /2), 2));s = S * earth_radius;s = Math.Round (S * 10000)/10000.0;return s;} This formula is correct in most cases, only when dealing with the relative points on the sphere, there is a problem, there is a modified formula, because there is no need to find out, can be found on the wiki. Of course, we all know that the earth is not really a ball body, but ellipsoid, so with the following formula:Code highlighting produced by Actipro Codehighlighter (fre

Portal: http://www.lydsy.com/JudgeOnline/problem.php?id=4540 Idea: Mo team again .... When we find that the left and right endpoints move, only the interval at the beginning or end of a point is added or removed First consider the right endpoint moving from R to R+1 Position p as the minimum value in [L,r] Then it will make a contribution to the p-l+1 interval in the newly added range to produce a[p]. Other left end points in [P+1,r], the right endpoint is the r+1 of the interval how to count it

. sin (g );Var sl = Math. sin (l );Var sf = Math. sin (f );Var s, c, w, r, d, h1, h2;Var a = EARTH_RADIUS;Var fl = 1/298. 257;Sg = sg * sg;Sl = sl * sl;Sf = sf * sf;S = sg * (1-sl) + (1-sf) * sl;C = (1-sg) * (1-

} lat2* @param {Object} lng2*/function Getflatterndistance (lat1,lng1,lat2,lng2) {var f = Getrad ((lat1 + lat2)/2);var g = Getrad ((LAT1-LAT2)/2);var L = Getrad ((lng1-lng2)/2);var sg = Math.sin (g);var sl = Math.sin (l);var sf = Math.sin (f);var s,c,w,r,d,h1,h2;var a = Earth_radius;var fl = 1/298.257;sg = SG*SG;SL = SL*SL