Java to guess the number of games randomly given a number, guess the size until the correct, java to guess the number
Package com. swift; import java. util. random; import java. util. extends; public class GuessBigSmall {public static void main (String [] args) {scan = new external (System. in); Random random = new Ran
Using System;Using System.Collections.Generic;Using System.Linq;Using System.Text;Using System.Threading.Tasks;Namespace Eluosi{Class Program{static void Main (string[] args){New program (). Play ();}void Play (){Random r = new Random ();Int J = R.next (1, 10);int i;int n=1;Console.Write ("Guess what the random number is (1~10):");Do{i = Int. Parse (Console.ReadLine ());if (i = = j){Console.Write ("Congratulations on your guessing at {0} times", N);}E
This article describes the Java implementation of the simple guessing game code. Share to everyone for your reference.
The following is a reference fragment of a guess number game in the Java language:
Import Java.text.SimpleDateFormat;
Import Java.util.Date;
Import Java.util.Scanner;
Main function public class Calssone {public static void main (string[] args) {//shit+ctrl+o int result;
Randomly produces a
The account of the network game player is stolen maliciously, the equipment is looted, this kind of thing happened too much. From time to time we can see the news: "Hackers embedded in internet cafes machine Trojan virus, attempt to steal online game account ..."
In the world of online games, one of the best equipment does not know how much money, effort and sleepless nights, so the most worrying thing for players is that they are being used as virtua
This article describes the go language to realize the method of guessing the number of small games. Share to everyone for your reference. The specific analysis is as follows:
Randomly generated a number, enter a number to see whether the pair, matching the knot speed, the other tip is big or small
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Every year children's Day, Nowcoder will prepare some small gifts to visit the orphanage children, this year is also the case. HF as the senior veteran of the Nowcoder, naturally also prepared some small games. Among them, there is a game like this: first, let the children surround a big circle. Then, he randomly assigned a number m, so that the number of childre
Description:
Every year on Children's Day, jobdu prepares some small gifts to visit children in the orphanage. This year is also the case. As a veteran of jobdu, HF has also prepared some games. Among them, there is a game like this: first, let the children form a big circle. Then, he randomly specified a number M to let the number of children numbered 1 start to
count, and infer directly.
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Also see others have a way of thinking, directly find the law, according to the rule of violence solution.
Divided into two parts to consider, the boundary situation is directly 2*n-2, the intermediate interval is two number cycle change.
#include
A different way of thinking. Direct simulation, according to the first order, after the reverse of the simulation;
- { +count+=high*flog; A } at Else if(1==now)//the current number is 1 o'clock Count - { -count+=high*flog+low+1; - } - Else - { incount+= (high+1)*flog; - } toflog=flog*Ten;//number One left shift + } - returncount; the } * voidMain () $ {Panax Notoginseng intnum; - intmax=0; thecout"Please enter a value to test:";
= =. And then, a look at the amount of data if a single processing must be timed out. So I thought of all the processing into one treatment. and then, using CT to represent all the processing after the reversal of the transformation =1 is not flipped, =-1 for flipping. Two flips is equivalent to not flipping. CT=-CT after each flip. use L to indicate the zoom factor after all processing. then the translation transformation and the flip and the scaling correlation, the processing is troublesome,
ImportRandomnum= Random.randint (0,100)PrintNumtimes=0Print "number[0,100] Guess game"Print "You'll have ten times to guess"Print "Guess out of range would game over immediately!"Guess= Int (Raw_input ("guess a number:") Times= times + 1 whileTimes : ifGuessorguess>100: Print "Your guess is out of range! Game over!" BreakElse: ifGuess >Num:Print "Too high,guess again!" elifGu
]) $ {Panax Notoginseng for(intj = i*i; J 2*i) - { theSU2[J] =0; + } A } the } + intK =0; - for(inti =0; i //Number of prime tables within n $ { $ if(Su2[i] = =1) su[k++] =i; - } - for(inti =0; I //find the number that satisfies P^k, where p is prime and K is a positive integer the { -LL mid =Su[i];Wuyi while
Transmission DoorDescriptionLele was bored in class recently, so he invented a number game to pass the time. The game is like this, first of all, he took out a few pieces of paper, respectively, 0 to 9 of any number (can be repeated to write a number), then he asked the classmate casually write two numbers x and K.The thing Lele to do is to re-spell the cards, ma
1 --set random number seed2 Math.randomseed(Os.time())3 Math.random()4 5 Print("Guess number Game (0-100)")6 7 LocalLimit =68 LocalAnswer =Math.random(0, -)9 Ten while true Do One Print("remaining".. Limit:"Second Chance:") A LocalGuess =Io.read("*number") - ifGuess = = Answer Then - Print("Congratulations, you guessed it! ") the Br
First, title:Given a positive integer in decimal, write down all integers starting with 1, to N, and then count the number of "1" that appears. Requirements: 1. Write a function f (n) and return the number of "1" that appears between 1 and N. For example F (12) = 5. 2. In the range of 32-bit integers, the maximum n of "f (n) =n" satisfying the condition is what.Two. Design ideas.Figure out the
The role of this program: using a computer to generate a random number within 100, the game to guess the number, guess is winning, guessing, the hint is big or small, continue to guess until the right to guess. At the end of the game, the comment is given and the number of times the player uses and guesses is calculated.of the program:Experience: Finally can desi
#include #include #include #include int main (int argc, const char * argv[]) {/*4 digits small to large no repetition 1-9A indicates the number of existing and positional pairsB means it exists, but the position is wrong1 2 3 41 4 6 81a1b*/int array[4] = {};BOOL Isexist = false;Set the seed of a random numberSrand ((unsigned int) time (NULL));for (int i = 0; i int temp = rand ()% 9 + 1;//1-9Determine if there isfor (int j = 0; J if (array[j] = = temp)
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