slim and sexy

1. Title Description: Click to open the link2. How to solve the problem: In essence, the Kruskal algorithm is used to generate MST. First, according to the Benquan value from small to large order, for a continuous edge set [L,r], if the n points are all connected, there must be a slender degree not exceeding w[r]-w[l] of the spanning tree. Therefore, can be small to large enumeration L, for each L, using the Kruskal algorithm to generate a minimum spanning tree, calculate the degree of thinness,

namespacestd; - -typedefLong LongLL; the Const intINF =0x7fffffff; - Const intmaxn=10005; - intP[MAXN]; - + structedge{ - intv,u,w; + BOOL operatorConstedge RHS)Const{ A returnwRHS.W;} at }; - - - - intFindintx) {returnP[x]==x? x:p[x]=find (P[x]);} - in intMain () { - intN,m,i,j,ans; to while(SCANF ("%d%d", n,m)!=eofN) { +Vectore; - Edge ee; the for(i=0; i){ *scanf" %d%d%d",ee.v,ee.u,EE.W); $ e.push_back (EE);Panax Notoginseng } - the sort (

]); - } - voidJointintAintb) + { -A=find (a); +b=find (b); A if(a!=b) pre[a]=b; at } - - - intKruscal (inti) - { - intq=Vect[i].first; in intp=Vect[i].second; - intCnt=0; to for(intI=0; ii; + - for(intJ=i; j) the { * intA=Vect[j].first; $ intb=Vect[j].second;Panax Notoginseng if(Find (a)! =find (b)) - { thecnt++; + if(cnt==n-1)returng[a][b]-G[q][p]; A Joint (A, b); the } + } - returnINF; $ } $ - intcal

Few points, sort by edge weights, enumerate enumerations L and R, check connectivity. Once connected, update the answer.Judge even General can O (1), before I was O (n) sentenced, previously written over, and later wrote T ... #include using namespacestd;Const intMAXN =101;Const intMaxe = maxn*maxn>>1;intn,m;intU[maxe],v[maxe],w[maxe];intPa[maxn];inlineBOOLcmpintAintb) {returnw[a]w[b];}intR[maxe];inlinevoidIdxsort () { for(inti =0; I i; Sort (R,r+m,cmp);}intFind (intx) {returnx==pa[x]?x:pa[x]=Fi

Topic Link http://poj.org/problem?id=3522kruskal+ and check the collection, attention to special cases such as 1, 0, 0, 1,1#include 2#include 3#include 4#include 5 using namespacestd;6 #defineMAXN 50057 structedge{8 intU,v,cost;9 };Ten intCompConstedge E1,ConstedgeE2) { One returne1.costE2.cost; A } - Edge ES[MAXN]; - intv,e; the intPAR[MAXN],RANK[MAXN]; - voidinit () { - for(intI=1; i){ -par[i]=i; + } - } + intFindintx) { A if(par[x]==x)returnx; at returnpar[x]=find (par[x]);

The problem with UVA is to make people bright, different from the naked tree water problem, the problem is slightly changed, not to seek the smallest spanning tree, but to find the most slender spanning tree.Because there are many spanning trees, the difference between the maximum and minimum edges of each spanning tree is uncertain. So you can only enumerate all spanning trees.Applying the minimum spanning tree template, we can enumerate the start position of the spanning tree, then push the en

(Exception $e) {Ob_end_clean (); Throw $e; }} if ($newResponse instanceof responseinterface) {//If route callback returns a Responseinter Face, then use it $response = $newResponse; } elseif (Is_string ($newResponse)) {//If route callback returns a string, then append it to the response if ($response->getbody ()->iswritable ()) {$response->getbody ()->write ($newResponse); }} if (!empty ($output) $response->getbody ()->iswritable ()) {if ($this

POJ 3522 Slim Span Given an undirected weighted graphG, You shoshould find one of spanning trees specified as follows. The graphGIs an ordered pair (V,E), WhereVIs a set of vertices {V1,V2 ,...,VN} andEIs a set of undirected edges {E1,E2 ,...,EM}. Each edgeEEHas its weightW(E). A spanning treeTIs a tree (a connected subgraph without cycles) which connects allNVerticesN-1 edges. The slimness of a spanning treeTIs defined as the difference between the l

the app needs to support the ipad version, then all you need to do is rewrite a view and put it in, the model and VC module also basically do not make any changes, think is not a little excited about it.Iii. SummaryThe use of MVC mode can be achieved to help VC slimming, can go to improve reusability and maintainability of the effect, but also let the original a whole business code, scattered to different places. In actual use we need concrete analysis of specific problems, if the things in a V

Link: Http://poj.org/problem? Id = 3522 Question: Slim Span Time limit:5000 Ms Memory limit:65536 K Total submissions:4962 Accepted:2587 Description Given an undirected Weighted GraphG, You shoshould find one of spanning trees specified as follows. The graphGIs an Ordered Pair (V,E), WhereVIs a set of vertices {V1,V2 ,...,Vn} AndEIs a set of undirected edges {E1,E2,...,Em}. Each edgeEεEHas its weightW(E). A Spann

Engineering in after many people, often appear more garbage, resulting in the packaging of the IPA file is large, sometimes we will clean up the code to the program to thin body, and slimming IPA effect obvious, mainly through the cleanup program of useless pictures.Recommend an app to clean up pictures https://github.com/tinymind/LSUnusedResourcesOpen run directly, click Browse. Select the project catalog, then click SearchSearch out the search tool think the project is not used in the pictures

breakthrough, that is, after the frame, he will pop up a dialog box, is this OK or cancel box.It is chosen as a breakthrough, because 1, the following list of data is read from the TXT file back to show, according to this line, you can find out how to get the data you want to display to the dialog box; 2 He is the picture on the frame after the Automatic popup dialog box, which helps you to understand how he gets the mouse click Interactive, Gets how the dialog box opens after the click Interac

Link: http://poj.org/problem?id=3522 Topic: Slim Span Time limit:5000ms Memory limit:65536k Total submissions:4962 accepted:2587 Description Given an undirected weighted graph G, and should find one of spanning trees specified as follows. The graph G is a ordered pair (V, e), where V is a set of vertices {v1, v2, ..., vn} and E is a set of undirected edges {E1 , e2, ..., em}. Each edge e∈e the

Ubuntu's sexy LOGO () Ubuntu refers to a national concept in South Africa, focusing on the loyalty and connection between people. Ubuntu's spirit is probably "the belief shared by the world connects everyone ". People with ubuntu spirit are open-minded and helpful. Active Communities are the driving force behind Ubuntu's development. This active force has gradually formed a unique Ubuntu culture. Today, I checked the previously collected Ubuntu LOGO o

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The UbuntuOne team officially released a new UbuntuOne icon, which is very sexy. (Remember, this is just Joey's idea. On the contrary, new icons will be ugly.) -- Benjamin's new look will be applied to the entire UbuntuOne website. The first stable Windows version is UbuntuOne, and an Android version will be released recently. But now, look at the poor old icon... The Ubuntu One team officially released the new Ubuntu One icon, which is very

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