spongebob character

D. Spongebob and SquaresSpongebob is already tired trying to reason his weird actions and calculations, so he simply asked you to find all pairs Of N and M, such that there is exactly x distinct squares in the table consisting of n rows and m columns. For example, in a 3x5 table there is 15squares with side one, 8 squares with side and 3 squares W ITH side Three. The total number of distinct squares in a 3x5 table is8 + 3 =. InputThe first li

Spongebob is already tired trying to reason his weird actions and calculations, so he simply asked you to find all pairs O f N and M, such that there is exactlyx distinct squares in the table consisting ofn rows and m Columns. For example, in a3?x?5 table there is squares with Side one,8 squares with side and 3 squares with side three. The total number of distinct squares in a 3?x?5 table is 15?+?8?+?3?=?26. InputThe first line

The number of blocks that are easy to get NXM isThen there is the question of summation, enumerating the n≤m of the two.Then it turns into a*m + c = x. A,m≥0,x≥c. The worst is n^3≤x, as for the middle will not explode, the test of 1e18 is good.#include using namespaceStd;typedefLong LongUll;vectorNs;vectorMS;//#define LOCALintMain () {#ifdef LOCAL freopen ("In.txt","R", stdin);#endifull x, T, C, a, N, m; Cin>>x; intK =0; //Ns.push_back (1); Ms.push_back (x); intEqu =0; for(n =1; ; n++) {T= N

Judgment question, a bit around, notice in the answer is not only a moment of judging conditions to be judged by B array#include #include#includeusing namespacestd;intb[110000],f[110000];mapint,int>Map,a;intMain () {intn,i,m; CIN>> N >>m; for(i=1; ii) {cin>>F[i]; if(! Map[f[i]]) map[f[i]]=i; Else{A[f[i]]=true; } } for(i=1; ii) {cin>>B[i]; if(!Map[b[i]]) {cout"Impossible"Endl; return 0; } } for(i=1; ii) {if(A[b[i]]) {cout"Ambiguity"Endl; return 0; }} cout"Possible"Endl; for(i=1; i

Simple question.#include #include#include#includeusing namespacestd;Const intmaxn=100000+Ten;intn,m;intB[MAXN],F[MAXN];intCNT[MAXN];intMain () {scanf ("%d%d",n,m); memset (CNT,0,sizeofCNT); for(intI=1; i) {scanf ("%d",F[i]); Cnt[f[i]]++; } for(intI=1; i"%d",B[i]); BOOLFail=0; for(intI=1; iif(cnt[b[i]]==0) fail=1; if(fail==1) printf ("impossible\n"); Else{fail=0; for(intI=1; iif(cnt[b[i]]>1) fail=1; if(fail) printf ("ambiguity\n"); Else{printf ("possible\n"); memset (CNT,0,sizeofCNT); for

;2000000|| I>p) Break; LL b= (i* (i+1)*(2*i+1)/6); ll c=i* (i+1)/2; if(k>=b (K-b)%c==0) {a[sum].x=i; A[sum++].y= (k-b)/c+i; } } if(a[sum-1].y==a[sum-2].x a[sum-1].x==a[sum-2].y) {printf ("%lld\n", (sum-1)*2); for(i=0; i) printf ("%lld%lld\n", A[I].X,A[I].Y); for(i=sum-3; i>=0; i--) printf ("%lld%lld\n", a[i].y,a[i].x); } Else { if(a[sum-1].x==a[sum-1].y) {printf ("%d\n", sum*2-1); for(i=0; i1; i++) printf ("%lld%lld\n", A[I].X,A[I].Y); for(i=sum-1; i>=

After the Spring Festival, the first day of work. Haha, today than the boss came early (Anxi, really enough dog legs). But the company is really warm ah, one took off a piece of clothing, at the same time, but also saw a lot of new faces, should be new to move colleagues. Morning also did not do, and colleagues exchanged greetings, of course, also took a lot of colleagues to bring food. I am too lazy this year, nothing brought to colleagues, table scold me AH: to deal with a large pile of mail,

The relationship between tts and character sets -- requires that the source and target database character sets must be the same, and the national character sets must be the same ., Tts Character SetThe relationship between tts and character sets -- requires that the source a

2016 Summary New Job The end of 2015, want to let oneself to a regular company, learn more things, "quit" to the original work. Give yourself more than 10 20 days of false, the beginning of the year to find a job, find 4 companies, originally

Unicode: Wide-Byte Character Set1. How to obtain the number of characters in a string that contains both single-byte and double-byte characters?You can call the Runtime Library of Microsoft Visual C ++ to contain the function _ mbslen to operate multi-byte strings (including single-byte and dual-byte strings.Calling the strlen function does not really know how many characters are in the string. It only tells you how many bytes are before the end of 0.

What is the Oracle character set? How to view the database character set? Explains how to modify the character set of oracle.1. What is the Oracle character set? The Oracle character set is a collection of symbols for the interpretation of byte data. It can be divided into d

Original URL: http://blog.163.com/magicc_love/blog/static/18585366220123111128283/Start PL/SQL Developer character encoding inconsistency errorDatabase Character Set (Al32utf8) and Client character set (ZHS16GBK) are different.Character set conversion may cause unexpected results.Note:you can set the client character s

You do not know the character set and encoding (encoding and character set encoding), but do not know the encoding character set. In my previous article, a friend proposed the differences between character sets and encoding. I will discuss it with you here. The difference between c