Read Catalogue I. IP Address Basics 1.1 IP Address structure and classification 1.2 special IP address 1.3 subnet mask 1.4 IP address request two. subnetting 2.1 subnetting Concept 2.2 Class C sub-network Division 2.3 subnetting Step 2.4 subnetting Case 2.5 sub-division Network considerations 2.6 Why

IP addresses are classified into five categories--------------------------------------------------------------------------------------------------------------- ----------------------------------------------------the meaning of the subnet mask and subnetting according to the subnet maskThe subnet mask is used to divide subnets. For example, a Class A network can hold 16777214 hosts. However, in practice, it is impossible to use a class A network only f

11111111Example of subnetting:1, a company to apply to a class C IP address, but to connect 6 subsidiaries, the largest one sub-The company has 26 computers, each subsidiary in a network segment, the subnet mask should be set to?A: Assume that the C network address is 192.168.0.0/24,6 subsidiary, namely Divide 8 subnets, two not, each subnet can hold 30 IP192.168.0.0-192.168.0.31/27-255.255.255.224192.168.0.32-192.168.0.63/27-255.255.255.224192.168.0

addresses: "192.168.5.253/30, 192.168.5.254/30"Broadcast address: "192.168.5.255/30"quickly divide subnets to determine IPLet's take example 2 for example:The topic requires that we divide the 192.168.5.0/24 network address into subnets that can accommodate 101/54/2 hosts. Therefore, we need to determine the host location, and then determine the network bit based on the host bit, and finally determine the detailed IP address.① determining the host bitSet the number of hosts that you need to be

LAN.WANThe last network segment is a WAN connection and requires 2 host addresses. Support WAN links with just 2 primary seats. 2^2-2 = 2.This leaves 8 bits to define the local subnet address. The next available address block is 172.16.2.192/30.Address: 172.16.2.192Binary representation:10101100.00010000.0000010.11000000Mask: 255.255.255.252Represents 30 bits in binary:11111111.11111111.1111111.11111100The IPV4 host address range provided is:172.16.2.193 to 172.16.2.194, broadcast address is 17

application, a company applied for a public network, such as 201.1.2.0/24, but the company has two groups, a group of the number of hosts is 6, the number of hosts in the other group is 4, and do not want the two groups of hosts to communicate with each other, if you apply for a public network , the cost is too high, so it is necessary to divide this network into multiple subnets. The subnet is divided by the first m bits in the host bit in the network address and the network address bits as th

mask calculation. Network ID Results We all know that the network ID part is unchanged, the host ID portion becomes 0, then in the calculation of the network ID, first look at how many bits in the subnet mask to represent the network, corresponding to the IP address conversion to binary only the previous few, such as 192.168.176.15/ 19, the network ID altogether 19 bits, then the network ID the first two bytes is 192.168.x.0 to change the third byte. So how do you quickly calculate the value o

subnets will need to occupy 1 bits of the original host identity bit. At this point the network number bit becomes 22 bits and the host label becomes 7 bits. Similarly borrowing 2 host bits can divide a class C network into 4 subnets ... How did the computer know if the network was divided into subnets?
This can be seen from the subnet mask. The subnet mask is as 32bit as the IP address, and the subnet mask is determined by using "1" for all corresponding bits that identify the network number i

First, a sample from a Shehiren teacher's book is referenced:Host H1 the process of sending packets to H2:First, with the subnet mask in the subnet:255.255.255.128 and target host H2 IP address:128.30.33.128 and get network number: 128.30.33.128. Obviously this does not match the network number of Subnet 1:128.30.33.0.The datagram is then forwarded by the default route R1 Subnet 1. At this point, R1 will look for its own routing table. Think of the host address and subnet mask of the H2, and whe

(' Enter the length of the first edge:'= float (input (' Enter the length of the second edge: ' = float (input (' Enter the length of the third side:'= (L1+L2+L3)/2= (p* (P-L1) * (P-L2) * (P-L3)) **0.5print(' Triangle area:%.2f'%s)Results:5, calculate the area of the circleR = Float (input (' Enter the radius of the circle:'= r**2*3.14print( The area of the circle is:%.2f '%s ')Results:6, draw a group of same cut roundImport turtleturtle.circle (turtle.circle)turtle.circle(())turtle.circle (

1. Hello world!Print("Hello world! ")2. Simple Interactive (interactive, file-style) textbook P19>>> name = input ("pleaseinput your name:")>>> please input Your name:poonprint(name)>>> Poon3, the user input two numbers, calculate and output two numbers of the sum:S1 = float (Input ("Please input the first num:")) S2= Float (Input ("Please input the second num:")) Sum= S1 +S2Print("The result is:%s"%sum)Print("The result is%.2f"% ((Float (input ("The first num is")) + (float (input ("The secibd

Hello world!Print ("Hello Word")Simple Interactive (interactive, file-style) textbook P19The user enters two numbers and calculates and outputs the sum of two digits:N1=input ("1") n2=input ("2:")Print (Float (N1) +float (n2))The user enters the triangular three-side length and calculates the area of the triangle: (Helen Formula)A = float (input ('input triangle First side length:')) b= Float (Input ('input Triangle Second side length:')) C= Float (Input ('input triangle Third side length:'))#Ca

Print ("Hello world!! ")Name=input ("What is your name?\n") where=input ("where is you now?\n") Age=input ("How is old is you ? \ n")Print("your name is {}". Format (name))Print("You live in {}". Format (where)Print("You is {} years old". Format (age))A=input (" Please enter first number:") b=input (" Please enter a second number:") Sum1=float (a) +float (b)print(" sum of two numbers: {}". Format (SUM1)) a=float (Input ( " first side length: " )) b =float (Input ( " second side length: "

Hello world!
Print ('helloWorld')
Simple Interactive (interactive, file-style) textbook P19
Name=input ('name=')print('{} Shi ver handsome '. Format (name)
the user enters two numbers, calculates and outputs two digits of the sum:
a=input ( " a= " ) b =input ( " b= " ) s =float (a) +float (b) print ( " {} " . Format (s))
the user enters a triangular three-edged length and calculates the area of the tr

First, the output Hello WorldPrint ("Hello Word")Second, summation operationA1 = input ("A1:"= input ("A2:"= float (A1) + float (A2) Print (" the first number {0} plus the second number {1} and is {2}". Format (a1,a2,sum))Three sides of the input triangle to seek the areaImport= input ("A1:"= input ("A2:" = input ("A3:"= (float (A1) +float (A2) +float (A3))/2D == d* (d-float (A1)) * (D-float (A2)) * (D-float (A3)) b=float (area) c= Math.sqrt (b)print(c)Four, the radius of the input circle, to

Hello world!Print ("hello,world!")
Simple Interactive (interactive, file-style) textbook P19Name=input (" Please enter name:")print("{} students, please study!") ". Format (name))
The user enters two numbers and calculates and outputs the sum of two digits:N1=input ("1:") N2=input ("2:") print (float (N1) +float (n2))
The user enters the triangular three-side length and calculates the area of the triangle: (Helen Formula)
A=input ("A:") b=input ("B:") C=input ( "C:") s= (f

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