blue square amsterdam

()) - return true; - Else - { A Get (x, y); + for(intK =0; k +; k++) the { - if(Inside (x,y,d[k])) $ { the if(!Vis[k]) the { the Fill (X,y,d[k],d[k]); theVIS[K] =1; - if(Dfs (x,y+D[k])) in return true; theFill (X,y,d[k],0); theVIS[K] =0; About } the } the Else the Break; + } - } the return f

Title: Square Number of rowsXiao Ming is looking at the number 203879 in a daze.Originally, 203879 * 203879 = 41566646641What's so magical about that? Carefully observed, 203879 is a 6-digit number, and its number on each digit is different, and it does not appear on all digits after the square to make its own number.There is a 6-digit number with this feature, please find it!Let's summarize the screening r

superfluous printing similar: "please enter ..." Redundant Content.1 public class_8 Four square and {2 public Static voidmain (string[] Args) {3Scanner Scanner =NewScanner (system.in);4 intn =Scanner.nextint ();5 intA = (int) (math.sqrt (n) +1);6 for(inti = 0; I ) {7 for(intj = i; J ) {8 for(intK = j; K ) {9 intm = (int) Math.sqrt (n-i*i-j*j-k*k);Ten if(i*i+j*j+k*k+m*m==N

{ for(i=0; i9; i++) { intJ; for(j=0; j//the numbers you fill in must be unused. { if(i==Take[j]) { Break; } } if(j==index) {S[a][b]=i; Take[index++]=i; if(b3)//indicates that the current line is not filled out{Fun (s,a,b+1); } Else//The current line is complete and starts on the next line { if(a2)//determines whether the current line is the last row{

The four-layer loop is likely to expire in direct violence. Here's a little trick.#include #include#includeusing namespacestd;inta[5000001];intMain () {intN; CIN>>N; intflag=0; for(intI=0; Iint) sqrt (n); i++){ for(intJ=i;jint) sqrt (n); j + +){ for(intK=j;kint) sqrt (n); k++){ intt=n-i*i-j*j-k*K; if(sqrt (t) = = (int) sqrt (t)) {//coutprintf"%d %d%d%d\n", I,j,k, (int) sqrt (t)); Flag=1; Break; } } if(flag==1) Break; } if(flag==1)

Test instructionsFour squared sum theorem, also known as Lagrange's theorem:Each positive integer can be represented as a sum of squares of up to 4 positive integers.If 0 is included, it can be represented as a sum of 4 squares.Like what:5 = 0^2 + 0^2 + 1^2 + 2^27 = 1^2 + 1^2 + 1^2 + 2^2(^ symbol denotes the meaning of a exponentiation)For a given positive integer, there may be multiple representations of the sum of squares.Ask you to sort 4 numbers: 0 And for all possible representations press