magic square 5x5

Different constructor methods can be divided into three categories: Odd-order Magic Square, and 4MLevel magic and 4M+ Level 2 magic, whereinMIs a natural number, level 2 magic does not exist. 1 odd-order magic Construction Method

One: Odd magic square algorithm:1. The first element is placed in the middle column of the first row2. The next element is stored in the previous row and next column of the current element.3. If the previous row, the next column already has content, the next element is placed in the next row in the forefront.When looking for a row, the next row, or the next column, the matrix must be treated as a wrap.Algor

JavaScript to solve the third-order magic square Puzzle: Third-order magic Square, try to fill in a 3x3 table with the 1~9 9 different integers, making the sum of the numbers on each row, each column, and each diagonal. Strategy: Exhaustive search. Lists all the integer fill schemes, and then filters them. The brigh

4510 Magic square noip2015day1 T1time limit: 1 sspace limit: 128000 KBtitle level: Golden Gold SolvingView Run ResultsTitle DescriptionDescriptionMagic Square is a very magical n∗n matrix: It is made up of numbers, ..., n∗n, and the sum of the numbers on each row, column, and two diagonal lines are the same.When n is an odd number, we can construct a

Magic Square is a very magical n*n matrix: It is composed of digital three-way,..., n*n, and the sum of the numbers on each row, column, and two diagonal lines are the same. When N is an odd number, we can construct a magic square by the following method: First write 1 in the middle of the first line. Then, fill in eac

P1978 Magical Magic SquareDescribeMagic Square is a very magical n∗n matrix: It is made up of numbers, ..., n∗n, and the sum of the numbers on each row, column, and two diagonal lines are the same.When N is odd, we can construct a magic square by first writing 1 in the middle of the first line.Then, fill in each number

IOI ' The Magic Square (Magic version)The topic is translated by Jerryxie.Magic Square (Msqaure.cpp/c/pas)"Problem description"After the success of the Rubik's Cube, Mr. Lubic invented its two-dimensional version, called the Magic version. It is a table consisting of eight b

Time limit per test 2 secondsMemory limit per test 256 megabytesInput Standard InputOutput Standard output Little elephant loves magic squares very much. A magic square is a 3 hour x hour 3 table, each cell contains some positive integer. At thatThe sums of integers in all rows, columns and diagonals of the table are equal. The figure below shows the

This paper illustrates the method of realizing the odd-order magic square in C language. Share to everyone for your reference. The implementation methods are as follows: Copy Code code as follows: #include "stdio.h" #include "string.h" #include "Stdlib.h" #define N 5 void Main () {int a[n][n]={0};int i,j;int k; i = 0;j = N/2;A[0][j]=1;for (k = 2; k if (i = = 0 J = = N-1) {//First, deter

Magical Magic Square.View Submit Statistics QuestionsTotal time limit: 1000ms memory limit: 65535kBDescribeThe Magic Square is a very magical n*n matrix, with each row, column and diagonal, the numbers combined are the same.We can build a magic square in the following ways.

#-*-Coding:utf-8-*-#利用numpy模块构造幻方Import NumPyAs NP#列表循环向左移offset位DefShift_left(LST, offset):return [lst[(I+offset)%len (LST)]For IIn range (len (LST))]#列表循环向右移offset位DefShift_right(LST, offset):return [Lst[i-offset]For IIn range (len (LST))]#构造奇数阶幻方函数DefMagic_of_odd_order(n):p = (int) (N-1)/2)#创建矩阵1Initial_lst1 = List (range (p+1,n)) +list (range (p+1))INITIAL_MAT1 = []For IIn range (n):Initial_mat1.append (Shift_left (Initial_lst1, i))MAT1 = Np.array (INITIAL_MAT1)#创建矩阵2Initial_lst2 = List (ran

for(intj=0; j) -a[i][j]=0; - - intC=1; + intJ= (n1)/2; - for(inti=n-1; i>=0; i++) + { A if(c!=1 C-1)%n==0) at { - if(j==0) -j=n-1; - Elsej=j-1; - if(i==0) -i=n-2; in Else if(i==1) -i=n-1; to Elsei=i-2; + } -A[i][j]=c++; theJ + +; * if(c==n*n+1) Break; $ if(i==n-1)Panax Notoginsengi=-1; - if

When we see the sensitive geek words, we read this question first, and then calculate various la s on the paper... Question: Construct an anti-Magic Square (which seems to be the opposite of the Magic Square ). It is actually a simple search rule, My constructor: When the value is greater than or equal to the 5th order