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Here are a few ways to help you solve this problem. The PHP version converts the in HTML into a line break in a text box: Copy Code code as follows: function Br2nl ($text) { Return Preg_replace ('//i ', ', $text); }

I was in the company during the day to do the development of Linux systems, the evening back to home windows. Today in the company sent a mail, attachment is a notepad, back home to download the attachment, open Notepad, but changed the way, the

Recently has been doing that planning XML data detection tool, today is nearing the end, in doing that error report output, think the output in Notepad easier to see, so it realized. Later found in each error record, the output in Notepad turned

The original is because \ after a space of more than one    Attach an example that has just been written for debugging: [cpp]  View plain  copy #define DESAY_DEBUG (_string,myvalue)  \        do{\            c_ snprintf (desay_info, \              

purchase (1,0,0,0,0) is the same as the (0,1,0,0,0) effect. This can be simplified to allow the purchased book to increase (decrement) in accordance with this book, thus facilitating discussion. The parameters to be processed are the number of purchases for each volume, so recursion must be related to these five parameters. The parameters can be sorted in order from small to large. Discusses the number of arguments that are not 0, thus finding all possible types of discounts. The lowest price i

Clc Clear Syms X1 X2 X3 x4 X5 X6 x=[x1; x2; x3; x4; x5; X6]; Dxx=kron (x. ', X. '); % Note that when using symbolic function operations, you need to add a point after the variable "." % otherwise the default is the complex number, the result contains ConjThe result of the operation of the% Dxx=kron (x ', X ') is:% DXX =%% [Conj (x1) ^2, Conj (x1) *conj (x2), Conj (x1) *conj (x3), CONJ (x1) *conj (x4), Con

Rough Set TheoryIn the face of increasing databases, how can people find useful knowledge from these vast data? How can we refine what we have learned? What is a rough line description of a thing? What is a thin line description? Rough set theory answers the above questions. To understand the idea of rough set theory, we must first understand what is knowledge? Assume that eight blocks constitute a set, a = {x1, x2, X3, X4, X5, X6, X7, X8 }, each bl

dimensional inverse discrete cosine transform */// fidct_init() MUST BE CALLED BEOFRE THE FIRST CALL TO THIS FUNCTION!void fidct(short *const block){static short *blk;static long i;static long X0, X1, X2, X3, X4, X5, X6, X7, X8; for (i = 0; i {blk = block + (i if (!((X1 = blk[4] (X5 = blk[7]) | (X6 = blk[5]) | (X7 = blk[3]))) {blk[0] = blk[1] = blk[2] = blk[3] = blk[4] = blk[5] = blk[6] = blk[7] = blk[0]

/*The problem of 10^8 violence can be answered but slow ..... There is a small bug that the person card int but did not pay attention to short with short can not hash directly to engage49428K 313MS */#include#include#include#defineBase 12500000using namespacestd;intA1,a2,a3,a4,a5,x1,x2,x3,x4,x5,ans; Shortf[12500000*2+ -];intMain () {scanf ("%d%d%d%d%d",a1,a2,a3,a4,a5); for(x1=- -; x1 -; x1++)if(x1) for(x2=- -; x2 -; x2++)if(x2) {ints=a1*x1*x1*x1+a2*x

Using the Library of functions:#include #include #include Source Code (addition):#include #include #include int main (void) { char s1[100],s2[100],s3[100],s4[100],s5[100],s6[100]　　//because it is a sub-total program, please ignore the extra long N=-1,n1=0,n2=0,n3=0,x1,x2,x3,x4,x5,x6,y3,y4 scanf ("%s ", S5)　　　　　　　　　　　　　　　　　　　　　　//input string s5 scanf ("%s ", S6)　　　　　　　　　　　　　　　　　　　　　　//input string s6

enumerate, to see if all of the pins are selected, then the enumeration of {0, ..., 0} to {1, ..., 1}, which requires 2 of the n-th-exponent. Obviously, when n is large, the efficiency of this approach is very low. The implicit enumeration method introduced in this paper can improve the efficiency of solving the optimal solution.The so-called implicit enumeration method, in the literal sense, is to implicitly remove some cases that do not require enumeration, and from an example, the steps of t

. rtbbefore. text;String [] templines = tempbeforedata. Split ('\ n ');String [] tempsingleline = NULL;Foreach (string temp in templines){Tempsingleline = temp. Split ('= ');If (tempsingleline. Length = 2)Tempchangedata. appendformat ("{0} = {1}; \ n", tempsingleline [1]. Replace (";", ""), tempsingleline [0]);}This. rtbafter. Text = tempchangedata. tostring ();} private void btclear_click (Object sender, eventargs e) {{{} Private void btdatacodemake_click (Object sender, eventargs E){Datatable

factor to 4, and struct test takes the largest number of bytes in the float type X3, because the X3 occupies a byte number less than or equal to the set alignment factor of 4, So the struct or union whole needs to be aligned according to 4bytes, which means that the number of bytes struct or union must be divisible by 4, OK. struct test has taken up 9bytes, 10bytes cannot be divisible by 4, 11bytes is not, 12bytes is right; therefore, struct test eventually occupies the number of bytes 12bytes.

Private void button2_click (Object sender, eventargs E) { Datatable dt = This. gettable ("select * From sysobjects where xtype = 'U '"); For (INT I = 0; I { String tablebean = convert. tostring (Dt. Rows [I] ["name"]). toupper (). Replace ("WZ _",""); Datatable DTT = This. gettable ("select * from [" + convert. tostring (Dt. Rows [I] ["name"]) + "]"); System. text. stringbuilder sbshu = new stringbuilder ("using system ;"). append (system. environment. newli