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Starting 3 threads, thread 1 printing 1 to 5, thread 2 printing 5 to 10, thread 3 printing 11 to 15, then thread 1 printing 16 to 20, and so on ... Print until 30

Starting 3 threads, thread 1 printing 1 to 5, thread 2 printing 5 to 10, thread 3 printing 11 to 15, then thread 1 printing 16 to 20, and so on ... Print until 30 public class Mainthread {private static int num;//current reco

1, 2, 3, 5, 7, 8, 10, 11, 12, 13, 14, 15, 16, 21, 22-"1 ~ 3, 5, 7 ~ 8, 10 ~ 16,21 ~ 22

In order to omit the space and make it visible to the operator who manually fills in the paper, the volume number on the card of the materials shelf is determined to be classified and sorted, as shown in A-3, A-4, A-5, A-8 forming A-3 ~ 5, 8, etc. The following code uses a few auxiliary list /// /// Similar to 1, 2, 3

An array of integers and the largest contiguous subarray, for example: [1, 2,-4, 4, 10,-3, 4,-5, 1] The largest contiguous subarray is [4, 10,-3, 4] (to be stated and programmed)

$arr= [1, 2,-4, 4, 10,-23, 4,-5, 1]; $max _sum= 0; $sum=0; $new= []; $i= 1; Echo' ; foreach($arr as $key=$value ){ if($sum){ unset($new[$i]); $i++; $sum=$value; }Else{ $sum+=$value; } $new[$i][] =$value; if($max _sum$sum){ $max _arr=$new; $max _sum=$sum; } } Print_r($max _sum

Using regular expressions to implement the Operation Express = ' 1-2* ((60-30 + ( -40/5) * (9-2*5/3 +7/3*99/4*2998 +10 *568/14))-( -4*3)/(16-3*2)) '

#!/usr/bin/env python# Coding:utf-8Import Redef Dealwith (Express): Express.replace ('+-','-') Express.replace ('--','+') returnexpressdef Col_suanshu (exp):if '/' inchexp:a,b= Exp.split ('/') returnStrfloat(a)/float(b))if '*' inchexp:a,b= Exp.split ('*') returnStrfloat(a) *float(b) def get_no_barcate (Express): Express=express.strip ('()') Print ('>>>', Express) whileTrue:ret= Re.search ("-?\d+\.? \d*[*/]-?\d+\.? \d*", Express)ifRet:res=Col_suanshu (Ret.group ()) Express= Ex

[]AS3 algorithm instance] Output 1 to the maximum number of n digits title: input number n, sequentially output from 1 the largest n bits 10 binary number. For example, input 3, the output 1, 2, 31 until the maximum 3 digits is 999. 】

Idea: If we were to fill 0 in front of the number , we would find that the N-bit all 10 binary number is actually N from 0 to 9 of the full array. That is to say, we arrange each digit of the number from 0 to 9, and we get all the 10 binary numbers. 1 /**2 *ch Storing numbers3 *n n Number of digits4 *index Count Value5 **/6 Private functionNum (ch:array,n:int,ind

"C language" with Π/4≈1-1/3 + 1/5-1/7 + ... The formula finds the approximate value of π until the absolute value of an item is found to be less than 10^6.

With Π/4≈1-1/3 + 1/5-1/7 + ... The formula finds the approximate value of π until the absolute value of an item is found to be less than 10^6. #include "C language" with Π/4≈1-

"C language" with Π/4≈1-1/3 + 1/5-1/7 + ... The formula asks for the approximate value of π until the absolute value of an item is found to be less than 10^6. __c language

With Π/4≈1-1/3 + 1/5-1/7 + ... The formula asks for the approximate value of π until the absolute value of an item is found to be less than 10^6. #include

Optimizing Nginx server configuration in CentOS (1/3)

/usr/local/nginx/logs/nginx_error.log crit;Pid/usr/local/nginx/logs/nginx. pid;Worker_rlimit_nofile 204800;Events{Use epoll;Worker_connections 204800;}Http {Include mime. types;Default_type application/octet-stream;Log_format main '$ remote_addr-$ remote_user [$ time_local] "$ request "''$ Status $ body_bytes_sent "$ http_referer "

2016/1/10 Job 1, two-dimensional array traversal output summation 2, transpose operation???? 3, nine Gongge?? The latter two exist problems

matrix two-dimensional array in } - Private Static voidPrintArray (int[] arr1) to //??? How it came to be, why did it happen? + { - //The fourth step is to establish a two-dimensional array arr2 The index traversal output assignment. the for(inti=0;i){ * for(intj=0;j){ $System.out.print (arr1[i][j]+ "");Panax Notoginseng }system.out.println (); - } the } + A}Three, nine Gongge1 Public classninetable {2

10. Dynamic Planning (3) -- 0-1 backpack problem, 0-1 backpack

10. Dynamic Planning (3) -- 0-1 backpack problem, 0-1 backpack In the previous article "9. Dynamic Planning (2) -- Subsets and problems", we talked about Subsets and problems and their implementations. Backpack problems are actually a subset and a type of problem, but the problem is not "determining the problem" but "o

2016/1/10 Example 1, console input number 2, console input corresponding number of results 3, the sum of the results and the maximum minimum value of the average

bubbling Algorithm > [0] is the minimum value - for(intj=0;j//number of rows to compare to for(inti=0;i//Number of comparisons (number of columns) + //the more rows you compare, the fewer times you need to compare the number of accompanying numbers, and the less you need to-j the last number so you don't have to compare so-1 - if(t[i]>t[i+

Question 10: Use recursive algorithms to design functions and calculate 1*3*5*7 *... * (2n-1 ).

/*************************************** ************************C LanguageAUTHOR: liuyongshuiDATE :************************************************ ***********************//*Question 10: Use recursive algorithms to design functions and calculate 1*3*5*7 *... * (2n-1 ). */ # Include Long fac (int n); // original funct

What is the change in the Windows 10 interface? Flat style thick (1/3)

original white space is now occupied by smaller, more complex projects, which are still conspicuous and readable, but are much finer than the tiles that occupy Windows 8. Blue seems to be the new favorite of Microsoft, which is the color theme they use at the conference, and it is also reflected in a number of newer icons. While this is reminiscent of Mac OS X, which also has a lot of blue icons, the difference between two systems is limited to that. In addition to color,

Career Success factors: 1 goal, 2 basis points, 3 tips, 4 ideas, 5 points of luck, 6 Requirements, 7 points of learning, 8 points of communication, 9 points of habits, 10 points of self-confidence, 11 traps, 12 points of effort

: before the age of 35, you must train your speech skills. Many successful people are first of all excellent speakers. Chapter 9: 9 habits The power of habits is amazing. The habits you developed before the age of 35 determine the size of your success.1. Good habits of positive thinking.2. develop a good habit of efficient work-learn to like and get used to your office; be cautious in your life, but be cautious in your work; learn to listen and

Career Success factors: 1 goals, 2 basis points, 3 skills, 4 ideas, 5 points of luck, 6 requirements, 7 points of study, 8 points of communication, 9 habits, 10 points of confidence, 11 traps, 12 points of effort "excerpt"

positive thinking.2. Develop a good habit of working efficiently--learn to like and get used to your office; Life can be informal, but work must be cautious; Learn to listen and not interrupt others to speak.3. Develop a good habit of exercising your body.4. Good habits of a wide range of hobbies.5. Good habit of quick action. The Tenth chapter: very confident1. Self-confidence is the spiritual pillar of success.2. Confidence can win the trust of o

Use malloc to allocate 2 kb space, and then use realloc to adjust to 6 kb, 1 MB, 3 MB, and 10 MB space, and fill these five memories with "A", "B", "C", "D", and "E" respectively.

# Include # Include # Include # Include Int main (void) { Char * str1 = NULL; Char * str2 = NULL; Char * str3 = NULL; Char * str4 = NULL; Char * str5 = NULL; Str1 = (char *) malloc (2*1024 * sizeof (char )); If (str1 = NULL) { Printf ("malloc error! \ N "); Return-1; } Printf ("malloc 2kb: % P \ n", str1 ); Memset (str1, 'A', 2*1024 * sizeof (char )); Printf ("mem content: % s \ n", str1 ); Str2 = (char *) realloc (str1, 6*1024 * sizeof (char )); If (

C Language Code Programming questions Summary: Show expression of 1*2+3*4+...+9*10 representation

Displays the representation of an expression 1*2+3*4+...+9*10The source program code is as follows:1 /*2 June 7, 2017 22:54:513 function: Implementation of 1*2+3*4+...+9*10 expression operation4 5 */6#include"stdio.h"7#include"str

[Openstack Storage] RAID 0 1 2 3 4 5 6 10 01 30 50, soft RAID, hard raid

this time, the third and fourth disks are idle. When B data is written to the third Disk in a certain band, and B data is checked in the fourth disk, in this way, both data a and data B can be read and written at the same time. VII. Raid 6 Raid 6 adds a verification area on the basis of RAID 5, each of which has two verification areas. They use an unused verification algorithm to improve data reliability. Next we will introduce several types of combined raid

10 floors for programmers (1 ~ Layer 3)

ArticleDirectory Layer-3 cainiao Layer-3 prawns Layer-3 cool man Program 10 floors Since the western Renaissance, China lags behind the West in natural science, and the software field is no exception. Of course, many programmers in China may have many different opinions on this. Some people think

MIT 6.828 Jos Study Note 10. Lab 1 part 3:the kernel

the caller's stack frame. Where our function is to get the value of the current stack frame EBP register, and the return address in the caller's stack frame, the input parameters passed to the current stack frame.So, according to the distribution of the data in the graph, we can know that the value of the register EBP is the highest address of the current stack frame, and that the memory unit that corresponds to the highest address is exactly the highest address of the caller's stack frame.The

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