online programming practice

The code is as follows:The title means that a list of lists is displayed in a well-organized table by a function, with the right alignment of each columnTabledata = [[' Apples ', ' oranges ', ' cherries ', ' banana '], [' Alice ', ' Bob ', ' Carol ', ' David '], [' Dogs ', ' cats ', ' Moose ', ' goose ']‘‘‘Apples Alice DogsOranges Bob CatsCherries Carol MooseBanana David Goose‘‘‘#输出每一列右对齐 I don't think it should be the last line of string,#但是书上的不是啊, it bothered me

7-12(1) Find the position of the element item in the given array arr:function IndexOf (arr, item) { var flag =-1; for (var key in arr) { if (arr[key] = = Item) { flag = key; } } return flag;}(2) calculates the sum of all the elements in the given array of arrfunction sum (SRR) { var sum = 0; for (var key in arr) { sum + = Arr[key]; } return sum; }(3) Remove the array of all values in arr that are equal to item, do not directly modify t

("Minimum score:" +computer); } Else{System.out.println ("Minimum score:" +min); } } Public voidTell () {System.out.println ("Name:" + name + "study Number:" +Stuno); System.out.println ("Math Score:" + math + "English score:" + 中文版 + "Computer score:" +computer); }}classstuinfo{ Public Static voidMain (string[] args) {Student person=NewStudent (); Person. Stuper ("2015025500", "Zhang San"); Person.stugrade (50,60,70); Person.tell (); Person.count (); } }The result of th

() method when there is a layout switch. Modify the Updatephotoview () method in the Crimefragment () method.1 Private voidUpdatephotoview (intWidthintheight) {2 if(Mphotofile = =NULL|| !mphotofile.exists ()) {3Mphotoview.setimagedrawable (NULL);4}Else {5Mbitmap =Pictureutils.getscaledbitmap (Mphotofile.getpath (), width,height);6 Mphotoview.setimagebitmap (mbitmap);7 }8}The width and height of the two parameters are added, so the Updatephoto method is scaled according to the pa

Read end Shut_wr Close the Write end Shut_rdwr Both read and write off Close terminates two directions of data transfer, shutdown can selectively terminate data transfer in a certain direction or terminate data transfer in two directionsSHUTDOWM How=1 can guarantee that the peer receives an EOF character, regardless of whether other processes have opened the socket.Close does not guarantee that it will be sent until the socket reference count is re

sent, call the function gethostbyname () to resolve Host B, and convert the hostname to a 32-bit IP address. This process is called DNS domain name resolution .Step b:ping program sends an ICMP echo packet to the destination IP addressStep c: Convert the destination host's IP address to a 48-bit hardware address , send ARP request broadcasts within the LAN, and find the hardware address of Host B.Step d: After the ARP protocol layer of Host B receives the ARP request from host A, the hardware a

, blocking mode), if the length of the data being written is less than the waiting pipe_buf, either all bytes are written, or none of the bytes are written. If all of the write requests are destined for a blocking FIFO, and the data length of each write request is less than or equal to Pipe_buf bytes, the system ensures that the data will never be interleaved. (Refer to my previous blog post). Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reprodu

=" Http://s1.51cto.com/wyfs02/M02/7A/37/wKiom1alvg_xEQYNAAAUS7Ts9i0693.png "title=" User.png "alt=" Wkiom1alvg_xeqynaaaus7ts9i0693.png "/>Displays the shell for the account and account, and the TAB key between the account and the shell650) this.width=650; "src=" Http://s3.51cto.com/wyfs02/M02/7A/37/wKioL1alv1ej_LDzAAAh7atkY0o125.png "title=" Awk.png "alt=" Wkiol1alv1ej_ldzaaah7atky0o125.png "/>3. Retrieving IP650) this.width=650; "style=" width:630px;height:326px; "src=" http://s5.51cto.com/wyfs

type parameter (that is, the received signal code), which itself is of type void, handler can also be the following two special values:sig_ign Shielding the signalSIG_DFL Restore default behaviorExample 1void handler (int sigNum) { cout RETURN VALUESignal () returns the previous value of the signal handler, or Sig_err on error.In the event of a error, errno is set to indicate the cause.int main (int argc, char *argv[]) { sighandler_t Oldhandler = Signal (SIGINT, handler); if (Oldhandle

An object that cannot be modified after the creation state is called an immutable object . Immutable objects are inherently thread-safe. Their constants (fields) are created in the constructor. Since their state cannot be modified, these constants will never change. immutable objects are always thread-safe . An object is immutable only if it satisfies the following state; Its state cannot be modified after it has been created; All fields are final type; It is created correc

;data; T->data=s->data; S->data=temp; } }} p=p->Next; Y--; } returnq;}intMainintargcChar*argv[]) {List List; Linknode* head=NewLinknode; Head->next=NULL; Linknode*sort; Linknode*tail; Tail=Head; stringstr; CIN>>str; while(str!="Exit") {Longintegernode*Phead; Phead=list.creat (str); Tail=List.add (Tail,phead); CIN>>str; } Sort=list.sortpart (Head,1,2); List.output (Head); cout"outputs the specified sort sequence"Endl; List.show (Sort,2); System ("PAUSE"); returnexit_success;}C + +

Rewrite requirement 1: Overwrite as pointer to data structure#include 　　C + + Programming Practice Guide 1.1 delete sequence in the same number rewrite requirement implementation

Rewrite requirement 1: Rewrite to represent a two-dimensional array in a single-linked list#include 　　C + + Programming practice Guidance 1.2 operation of two-dimensional array rewriting requirements implementation

Rewriting requirements: Overloading >> and #include #includeusing namespacestd;classfract{intNum,den; Public: Friend Ostreamoperatortemp); Friend IStreamoperator>> (istream intput,fractTemp1); Fractoperator+ (fractTemp1); intgcdintMintN) {intR; if(mN) {R=m;m=n;n=R; } while(r=m%N) {m=N; N=R; } returnN; }};istreamoperator>> (istream input,fractTemp1) {Input>>temp1.num>>Temp1.den; returninput;} Ostreamoperatortemp) {Output"/"Endl; returnoutput;} Fract Fract::operat

Exercise 1: (1) Create a class in a package that creates an instance of the class outside the package where the class is located.Import Mil.oms.main.test.Test; Public class maintest {public static void Main (String args[]) { Test test=new test (); } /** Run result test () instantiation ... Package Mil.oms.main.test;public class Test{public Test () {System.out.println ("Test () instantiation ...");}Exercise 2: (1) rewrite the code snippet in this section as a c

1#include 2 using namespacestd;3 4 voidTo_lower (Char*s)5 {6 while(*s!=' /')7 {8 if(*s>='A'*s'Z')9*s+= +;Tens++; One } A } - - Char* STRDUP1 (Const Char*s) the { - Char*p=New Char[]; -coutsizeof(s) //////////Note - inti; + for(i=0; s[i]!=' /'; i++) - { +p[i]=S[i]; A } atp[i]=' /'; - returnp; - } - - Char* FINDX (Const Char*s,Const Char*x) - { in intI=0; - while(*s!=' /') to { + while(* (S+i) ==* (x+i) * (x+i)! =' /') -

() { while(true) {clerk.saleproduct (); Try{Thread.CurrentThread (). Sleep (10); } Catch(interruptedexception e) {e.printstacktrace (); } } }}/*** Created by Bruce on 2018/7/22.*/ Public classProducerandconsumer { Public Static voidMain (string[] args) {Clerk Clerk=NewClerk (20); Thread T1=NewThread (NewProducer (clerk)); Thread T2=NewThread (NewConsumer (clerk)); Thread T3=NewThread (NewConsumer (clerk)); Thread T4=NewThread (NewConsumer (clerk)); T1.setname (Producers); T2.setname ("Consu

following. How do I tell if the first sentence is successful?echo $? The output execution succeeded (returning 0 indicates that it was executed correctly, otherwise it failed.) ）Here the echo output of 0 is above the return0;After modification:# include intint argv,Char* argc[]) { printf (" Hello word"); return 101 ;}GCC main.c-o main2.out ./main2.out to output normallyecho $? The output is 101../main2.out ls Here you can only output the operating results normally. The LS command is no

myinput in keywords: print "Chars can not contain the keywords" if myinput[0] not in Alphas: print "Invalid:first symbol must is a Lphabetic " else: for Otherchar in myinput[1:]: if Otherchar not in Alphas +nums: print" ' Invalid: Remaining symbols must is alphanumeric "break Else: print" Okay as an identifier "else: print" the Word is illegal identif

: = Fp.readlines () for in data: Print(re.sub ( '\[email protected] (\w+.?) +"[email protected]', line). Rstrip ())Results:27. Extract the month, day, and year from the timestamp and then format "Month, day, year".Importref= Open ('Redata.txt','R') with open ('Path\redata2.txt','R') as Fp:data=Fp.readlines () forLineinchdata:m= Re.match ('^\w{3}\s (\w{3}) \s{1,2} (\d{1,2}) \s\d{2}:\d{2}:\d{2}\s (\d{4})', line)Print('%s,%s,%s'% (M.group (1), M.group (2), M.group (3)))Results:Pytho