sql days in year

onTo say there is an article table article, the time to store an article's added article is the Add_time field, which is an int (5) type, you now need to query the total number of articles added today and sort by time from large to small, then the

SQL Server has a very powerful function: DATEPART ()It can calculate that 2017-10-17 is part of this year'sDay of the week: Select DatePart (dy, ' 2017-10-17 ')Week: Select DatePart (wk, ' 2017-10-17 ')First month: Select DATEPART (mm, ' 2017-10-17 '

Mysql calculates the number of days before the birthday (after this year, it will be calculated as per the year) bitsCN.com How many days does mysql computing have before its birthday (after this year, it will be calculated as per the year) Table 1

SQL statement used to determine whether a given date is in a leap year -- declare @ datedatetime based on the total number of days of the year; set @ dategetdate () selectcasedatediff (day, dateadd (year, datediff (year, 0, @ date), 0), dateadd

I. Annual ENQUIRY Enquiry data for the yearSELECT * fromblog_articleWHERE Year(From_unixtime (Blogcreatetime))= Year(Curdate ()) Second, query quarterly data query data with quarter numberSELECTArticleID, Quarter (from_unixtime (' Blogcreatetime ')

-- Calculate the number of Sundays in a month of a year (excluding Saturday) Create Function f_getnums (@ year_month varchar (8) returns INTAS begin declare @ BDT datetime, @ EDT datetime, @ I int set @ I = 0 set @ BDT = cast (@ year_month + '-01'

Check this diary record SELECT * FROM Messages WHERE convert (Nvarchar, createdate, MR) = CONVERT (Nvarchar, GETDATE (),) Order by CreateD Ate DESC SELECT * from table WHERE DateDiff (day, column name , GETDATE ()) =0 Check this year SELECT

MySQL Query SQL statements today, yesterday, nearly 7 days, nearly 30 days, this month, and last JanuaryThis article mainly introduces the MySQL query today, yesterday, nearly 7 days, nearly 30 days, this month, the January of SQL statements,

DateDiff (Week,zy_time,getdate ()) =0//query this weekDateDiff (Month,zy_time,getdate ()) =0//enquire this monthThis season: SELECT * from table where DATEDIFF (Qq,c_calltime,getdate ()) =0First half year 1-6, after half year 7-12:select * from

This is the SQL script that calculates the first day of the one month:SELECT DATEADD (mm, DATEDIFF (Mm,0,getdate ()), 0)--the first day of the monthSELECT DATEADD (mm, DATEDIFF (Mm,0,getdate ())-1, 0)-the first day of the monthSELECT DATEADD