sql server inventory

Problem description: How can I find the remaining inventory of all products in the store based on the store ID? Business Description: remaining inventory of the product the total inventory records of the product andProblem description: How can I find the remaining inventory of all products in the store based on the sto

Problem Description: Find out the remaining stock of all items in the store according to the store ID? Business Description: The item's remaining stock = The total inventory record of the goods and-the total sales of the goods and. The database table structure after abstraction is as follows: Question abstraction: Use MySQL to check the remaining inventory information for all items in store 1th? Than

Tags: des code CTI Name table SQL/* Check the Inventory interface table */SelectMsi.segment1 Project Code,Msi.description Project Description,MSI.ORGANIZATION_ID Project organization number,A.ORGANIZATION_ID the organization number of things to deal with,A.transaction_quantity the number of things handled,A.source_code the source of things to deal with,A.transaction_source_name Thing handling NameFrom Inv.m

A few days ago, the inventory should be displayed when the school made a product release. The inventory is calculated by the difference between the incoming and outgoing goods. The main fields in the record table of incoming goods are as follows: PID is the product ID, num is the quantity, state is the status, and 0 is the incoming value, 1 is output. PID num state1 100 02 50 03 150 02 5 11 10 1

judge the main application hostname= grains[i]["id"]ipv4=str (grains[i]["IPv4"]). Replace (", ' 127.0.0.1 '", "") ipv4=ipv4.replace (",", " and ") mem=grains[i][" Mem_total "]/1024 +1num_cpu=grains[i]["Num_cpus"] os=grains[i]["Osfullname"]+grains[i]["lsb_ Distrib_release "]if "/data" notindiskusage[i]: disk_data= "None" else:disk_data =data_vol/1048576 ## #项目名为空 project= "" ## #通过minion id name to determine the main operating services, such as XX-MYSQL-1, then run mysql forjinapp_name: ifjinho

"ElseData_vol = Int (diskusage[i]["/" ["1k-blocks"])Print "Diskusage" + ":", data_vol/1048576### Remove 127.0.0.1 this addressIPv4 = str (grains[i]["IPv4"]). Replace (", ' 127.0.0.1 '", "")### because of some historical problems, the acquisition is not a hostname, but salt-minion of the ID Used to determine the main applicationhostname = grains[i]["id"]IPv4 = str (grains[i]["IPv4"]). Replace (", ' 127.0.0.1 '", "")IPv4 = Ipv4.replace (",", "and")MEM = grains[i]["Mem_total"]/1024 + 1NUM_CPU = gra

= Ssh.exec_command ("cat/etc/ntp.conf | grep Server | Xargs ") [1].read (). Strip ()Timezone = Ssh.exec_command ("Cat/etc/timezone") [1].read (). Strip ()swapiness = Ssh.exec_command ("cat/etc/sysctl.conf | grep swappiness | Xargs ") [1].read (). Strip ()Dns_resolv = Ssh.exec_command ("cat/etc/resolv.conf | grep nameserver | Xargs ") [1].read (). Strip ()Dns = Ssh.exec_command ("cat/etc/network/interfaces | grep dns ") [1].read (). Strip ()Repo = Int

: Count distinct (cardinality estimation) has been one of the SQL performance killers, if you can accept a certain error, you can use approximate algorithm. The approximate algorithm (NDV) has been implemented in Impala, and Presto is requested to blinkdb cooperation. Both are used Hyperloglog counting. Of course, not only count distinct can use approximate algorithms, but others, such as median, can also be used. ConclusionAlthough the relevant

---- Set a non-primary key to clustered index [Step 4] to: http://king123654789.iteye.com/blog/1169191 1. View All indexes. Clustered indexes are created on the primary key by default.Sp_helpindex person 2. -- delete the primary key constraint and remove the index constraint on the primary key queried in [1], for example, PK _ person _ 117F9D94. Remove the primary key constraint from the primary key field. This field is not the primary key.Alter table person drop constraint PK _ person _ 117F9

communicate with SQL Server, your application must use the SQL Server language. One of the methods is to use tools provided by SQL Server, such as the command column osql or SQL

Platform Description: Two SQL SERVER2005 servers with two identical databases installed on top of each otherRecently, because of the project needs, you need to copy the database on one of the servers on a database on another server, after a lot of Google has finally finished, here to do a detailed record, hoping to help everyone and themselves.One, the first step: SQL