, Degree descending query score all records of the table.SELECT * FROM Score ORDER by Cno Asc,degree DESCLINQ: (Here CNO ASC in LINQ to be written on the outermost)from S in ScoresS.degree DescendingS.cno AscendingSelect SLambda:Scores.orderbydescending (s = s.degree). (s = = S.cno)9. Check the number of students in "95031" class.Select COUNT (*) from student where class = ' 95031 'Linq:(from S in Studentswhere S.class = = "95031"Select S). Count ()Lambda:Students.where (s = = S.class = = "95031
StudentsS.class DescendingSelect SLambda:Students.orderbydescending (s = s.class)8, in CNO Ascending, Degree descending query score all records of the table.SELECT * FROM Score ORDER by Cno Asc,degree DESCLINQ: (Here CNO ASC in LINQ to be written on the outermost)from S in ScoresS.degree DescendingS.cno AscendingSelect SLambda:Scores.orderbydescending (s = s.degree). (s = = S.cno) 9. Check the number of students in "95031" class.Select COUNT (*) from student where class = ' 95031 'Linq:(from S
BadIRET vulnerability Exploitation
The Linux kernel code file arch/x86/kernel/entry_64.S versions earlier than 3.17.5 did not correctly handle errors related to the SS (stack) segment register, this allows the local user to initiate an IRET command to access the GS base address from the wrong address space to escalate the permission. The vulnerability, numbered CVE-2014-9322, was fixed by the Linux kernel community in November 23, 2014, with no public
are 37 F9 requests in total,Cancel the breakpoint, press ctrl + f9, and run the command to return. As follows:00AD3462 5E pop esi; kernel32.VirtualProtect00AD3463 5F POP EDI00AD3464 5B POP EBX00AD3465 C9 LEAVE00AD3466 C3 RETNYou can press f8. Then go to the following:00AD264D A1 6C5AAE00 mov eax, dword ptr ds: [AE5A6C]00AD2652 8A80 82370000 mov al, byte ptr ds: [EAX + 3782]00AD2658 8885 E8D1FFFF mov byte ptr ss: [EBP-2E18], AL00AD265E 0FB685 E8D1FFFF
" and select the code that supports service. cpp for MFC as follows:/*************************************** ***************************//* Module: Service. cpp *//* Author: inetufo *//* Email: Inetufo@thugx.com *//* Date: 2003/3/7 *//*************************************** ***************************/// Service. cpp: defines the entry point for the console application.//
# Include "stdafx. H"# Include "service. H"# Include "winsvc. H"# Include // header files required by the cregkey class# Inc
ORACLE converts data between milliseconds and dates, and oracle converts data between milliseconds.
Convert millisecond to date
SELECT TO_CHAR(1406538765000 / (1000 * 60 * 60 * 24) + TO_DATE('1970-01-01 08:00:00', 'YYYY-MM-DD HH:MI:SS'), 'YYYY-MM-DD HH24:MI:SS') AS CDATE FROM DUAL;
Date conversion in milliseconds
SELECT TO_NUMBER(TO_DATE('2014-07-28 17:12:45', 'YYYY-MM-DD HH24:MI:SS') - TO_DATE('1970-01-01 8:0:0', 'YYYY-MM-DD HH24:MI:SS')) * 24 * 6
Differences between equals and =, =, and equals
I. = and equals
1. = is an operator
2. equals is a String object method.
There are two types of comparison
1. Comparison of Basic Data Types
2. Comparison of referenced objects
1. Comparison of Basic Data Types
= Both equals and equals compare whether the values are equal. If they are equal, true is used; otherwise, false is used.
2. Comparison of referenced objects
= And equals both compare whether the addresses in the stack memory are equal. If t
", and the above is just the key value of the registry, the bottom line "you can still use this program % d ". In fact, this is the number of times you can use it. There should be a calculator here, but you don't have to worry about it. first go to the code and find a suitable place for breakpoint.004017DA 68 00014300 multi-open push program. 00430100; SOFTWAREAutoSoftMultRun2004017DF 68 02000080 push 80000002004017E4 FF15 0C604200 call dword ptr ds: [......004017FE FF15 08604200 call dword ptr
%dchars",s,strlen(s));getchar();return0;}
3 different sizeof editions strlen (char*) function is the actual length of the string, it is calculated from the beginning to meet the first ' "", if you only define the initial value is not assigned to it, the result is uncertain, it will be from the AA header address has been looking down until the encounter ' " Char Aa[10];coutA first examplechar* ss = "0123456789"; sizeof (
): Access violation - code c0000005 (!!! second chance !!!)*** ERROR: Symbol file could not be found. Defaulted to export symbols for F:\Program Files (x86)\Amazon\Kindle\Kindle.exe - eax=000000dd ebx=000004e4 ecx=00000000 edx=0022ed44 esi=0022ed68 edi=000000ddeip=0197383f esp=0022ed14 ebp=05920448 iopl=0 nv up ei pl nz na po nccs=0023 ss=002b ds=002b es=002b fs=0053 gs=002b efl=00210202Kindle!std::_Init_locks::operator=+0x13
strlen is defined:
Strlenget the length of a string. routine required header: strlen
2. Let's use several examples.
Example 1:
Char * Ss = "0123456789"; sizeof (SS) Result 4 ===" SS is the character pointer to a String constant sizeof (* ss) result 1 = "* ss is the f
Oracle time addition and subtraction
Recently, due to the time-frame addition and subtraction tests, I found some time addition and subtraction algorithms on the Internet, which can solve the pressing problem and help more Oracle beginners!
AdditionSelect sysdate, add_months (sysdate, 12) from dual; -- add 1 yearSelect sysdate, add_months (sysdate, 1) from dual; -- add JanuarySelect sysdate, to_char (sysdate + 7, 'yyyy-mm-dd HH24: MI: ss') from dual;
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