student grade program in c

the neuron S to Neuron T has no route, the output is "impossible". Otherwise the output is a number that represents the minimum speed ratio. If necessary, output an approximate fraction. Sample input23 21 2 22 3 41 33 31 2 101 2 52 3 81 3Sample output25/4Hint SourceThe sixth annual College student Program design competition in Henan provinceIdea: Enumerate the most speed of the edge, a strip of the speed i

, exclusive eggs have a certain length of L, and exclusive eggs always choose ai + AI + 1 +... + AI + L-1 reach the maximum parasitic position. If the surrounding heat is less than 0, the alien eggs choose sleep.How does an alien egg perceive its parasitic locations? Input Row 1: k indicates the number of groups of test data.Next, there will be 2 rows of test data in each group, 1st rows: l nRow 3: A1 A2 ...... An2 ≤ k ≤ 5 L ≤ n, 1 ≤ L ≤ 10 1 ≤ n ≤ 1000-100 ≤ AI ≤ 100There is a space between

. Kong wants to know how many Aurora points need to cover all lakes and oceans.2 ≤ K ≤ 5 1 ≤ R ≤ 50 1 ≤ N ≤ 100-100 ≤ Roxy PYi ≤ 100 | PYi | ≤ RR and PXi PYi are all integers. There is a space between data.Input> Row 1: K indicates the number of groups of test data.Next, we will test each group of data:Row 3: N R2nd ~ N + 1 rows: PXi PYi (I = 1 ,....., N)OutputFor each group of test data, one line is output: the minimum number of Aurora points required.Sample Input23 2

Student Program Design Competition (hangzhou) recommendliuyiding | We have carefully selected several similar problems for you:5943 5942 5941 5940 5939 Statistic |Submit |Discuss | Note Topic links:http://acm.hdu.edu.cn/showproblem.php?pid=5943Main Topic:Given s,n, put s+1,s+2, ... S+n This n number is filled to,..., n, requiring X to fill only the position of the factor x. (I.E. x%

Label: sp c r bs acm design program Table D Move bricks: In order to better attract excellent contestants to participate in the 39th ACM International College Student Program Design Competition, the global sponsors will be charged for participating in the competition and event hosting activities, the sponsors of the China Division shall provide funds for the re

ZZUOJ-1196-Monotonic (subject D, DP, the seventh ACM College Student Program Design Competition of Zhengzhou University) 1196: Monotonic number Time Limit: 2 Sec Memory Limit: 128 MB Submit: 35 Solved: 9 [Submit] [Status] [Web Board] Description For a positive integer x, if each digit of x is not greater than the number on the right side of x, then x is an incremental number, for example, 112,4557, 18

Four OperationsTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): Accepted submission (s): 18Problem Descriptionlittle Ruins is a studious boy, recently he learned the four operations!Now he want to use four operations to generate a number, he takes a string which only contains digits' 1 '-' 9 ', and split it into5 intervals and add the four operations ' + ', '-', ' * ' and '/' on order, then Calculate the result (/used as Integer division).Now yo

answer modulo.Sample Input223Sample Output34SOURCE2017 Chinese College Student Program design Contest-Girls ' special title Description: You have a necklace with n colors of red or blue beads, you can cut the necklace into a length of a number of beads, if the amount of red beads intercepted more than blue beads, it becomes good, Ask how many good possibilities there are. N=2,res=3;n=3,res=4;n=4,res=6;n=5

at each second of the shot. { if(vis1[i]==1) { intmax1=-1; for(intj=1; j) { intf=0; intsum=0; for(intK=j; k) { if(s[i][k]==1) {f++; } Else if(s[i][k]==-1) { if(f>=3) {sum+=f*2; if(sum>max1) {Max1=sum; } } Else{sum+=F; if(sum>max1) {Max1=sum; }} F=0;

; thevectorChar>v1; -vectorint>v2; -V1.push_back (str[0]); -V2.push_back (1); + intFlag =1; - + for(inti =1; I ) { A if(Str[i] = = str[i-1] ) { at inttemp = * (V2.end ()-1); -temp++; - V2.pop_back (); - V2.push_back (temp); - if(v2[1] = = v2[2] v2[0] >= v2[1] v1[2]-v1[1] ==1 v1[1]-v1[0] ==1) { -cout"YES"Endl; inFlag =0; - Break; to } + } - Else { the

; - if(tem==0) - { A intTem1=dot (V1,V2);//Vector collinear, judging the direction + if(tem10) the return 1; - return 0; $ } the } the intPuan_shun () the { the intans=0; - //dp[0][1]=1; in for(intI=0; i) the { the for(intj=0; j) About { thedp[j][i]=1; the for(intk=0; k) the { + if(If_shun (i,j,k)) -Dp[j][i]=max (dp[j][i],dp[k][j]+1); the }Bayians=Max (ans,dp[j][

89 3767 30 41 14 39 420Sample output15270Test instructions: A person to go shopping malls, parked in the smallest store location, stroll through all shopping malls, in return to the car to seek the length of the route. Solving: order, maximum minus 2. Balloons Topic Link: http://acm.sdut.edu.cn/sdutoj/showproblem.php?pid=2152cid=1172 Sample input511001001001111111010100100Sample outputCase 1:3 2Test instructions: The number of four connected blocks and eight blocks of 1. Puzzle: Full DFS templa

template problem for a dictionary tree#include #includestring.h>#includeusing namespacestd;#defineMAX 28structnode{intFlag//whether the tag is a node intnum;;//indicates how many times a dictionary tree has the same number of prefixes structNode *Next[max];};voidInsert (Node *root,Char*str) { if(root==null*str==' /') return ; Node*p=Root; intLast//num that records the last node that was passed while(*str!=' /'){ if(p->next[*str-'a']==NULL) {Node*temp=Newnode; for(int

(str2[i]!=','str2[i]!='}') b+=str2[i++]; S2[a]=b; I++; } intc1=0, c2=0, c3=0; for(It=s2.begin (); It!=s2.end (); it++) { if(!s1.count (it->First )) AA[C1++]=it->First ; } if(c1) Print ('+', C1); for(It=s1.begin (); It!=s1.end (); it++) { if(!s2.count (it->First )) AA[C2++]=it->First ; } if(C2) print ('-', C2); for(It=s2.begin (); It!=s2.end (); it++) { if(S1.count (It->first) s1[it->first]!=it->second) aa[c3++]=it->Fir

next n rows have m coordinates for each row (coordinates are given in a counterclockwise order, where the coordinates are integers)OutputOutput in the first few citiesSample Input5 5 2 42 0 4 0 4 4 2 4 2 0 6 0 6 6 2 6Sample Output2HINTThere must be an answer to that question . , and will only be in one city. (even if the city has overlapping) . and the polygon of a given city is convex polygons. SourceCompetition, do the most fun than a problem, simply ah, I am still silly X did not do it, bef