SelectTimediff ('23:40:00','18:30:00'); --subtract two time select substring (Timediff ('23:40:00','18:30:00'),1,5) ----“ to:Ten"Subtract back hours: minutesSelectDateDiff'2008-08-08','2008-08-01'); --7-----Two date subtractionSelectTo_days ('2008-09
Mysql sets two date formats to subtract. mysql sets two date formats to Subtract:
Original data table data:
Select (atime-btime) sec from data table;
The subtraction result is not a second. pay special attention to it!
Result:
To
Add and subtract functions for SQL Server Date: DATEDIFF DATEADDDATEDIFF: Returns the number of date boundaries and time boundaries across two specified dates, syntax: DATEDIFF (datepart, StartDate, enddate) minus EndDate with StartDateNote:
Original address: http://blog.csdn.net/xyzqiang/article/details/6577831Add and subtract functions for SQL Server Date: DATEDIFF DATEADDDATEDIFF: Returns the number of date boundaries and time boundaries across two specified dates, syntax: DATEDIFF
Before we know that SQL has the DateDiff () function, we need to calculate the date and time difference. I will directly put it in a program like php, asp, and asp.net for calculation, now I will share with you how to use the DateDiff function to
This is the SQL script that calculates the first day of the one month:SELECT DATEADD (mm, DATEDIFF (Mm,0,getdate ()), 0)--the first day of the monthSELECT DATEADD (mm, DATEDIFF (Mm,0,getdate ())-1, 0)-the first day of the monthSELECT DATEADD
Want to write a date of the addition and subtraction method, but it involves the judgment of the days of the month, if it is February, but also related to the judgment of leap years, some complex, the application process is always a problem, so
Transferred from: http://www.cnblogs.com/likwo/archive/2010/04/16/1713282.htmlQuery Day:SELECT * FROM table where to_days (column_time) = To_days (now ());SELECT * FROM table where date (column_time) = Curdate ();Query one week:SELECT * FROM table
Definition and usageDATEADD() function to add or subtract a specified time interval from a date.GrammarDATEADD(DatePart, Number, date)The date parameter is a valid day expression. Numberis the number of intervals you want to add; for future time,
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