2014 Beijing Network Competition 09, HDU 5040
This online competition is really miserable, and it's strange that I didn't think about the problem strategy. After I cut the water questions such as the sign-in question, I went to see the 06 frog
Wa is a dead question.
A person goes from the starting point to the target point. There is a camera in this process. The camera's illumination range is two units of length, including the camera's own position. There are two options to avoid being
Rescue
Time limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)
Total submission (s): 521 Accepted Submission (s): 217
problem DescriptionAngel was caught by the moligpy!
HDU-5025-Saving Tang Monk (BFS + priority queue), hdu-5025-savingbfsProblem Description Journey to the West (also Monkey) is one of the Four Great Classical Novels of Chinese literature. it was written by Wu Cheng 'en during the Ming Dynasty. in
Description: A 9-10-11 wooden board with a length of 9 + 10 + 11. However, the cost of splitting a wooden board with a length of 1 is L. Therefore, the minimum cost of splitting is required.
Algorithm: Construct a user-defined tree. Put
Idea: first sort the gas stations in ascending order.
Add B [I] to the priority queue when passing through a gas station (pre-store the amount of fuel each time it passes through a gas station)
When the fuel tank is empty: 1. If the queue is empty
Reprinted please indicate the source: http://blog.csdn.net/u012860063
Question link: http://poj.org/problem? Id = 3253
Description
Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he
Question link: http://poj.org/problem? Id = 2049
The plot of the story "bottom story" is used, and the little ugly fish, Tom, is lost. His father is trying to help him.
The question shows a map like this, which assumes that the map is composed of
From: http://blog.csdn.net/svitter
Question 12: Computer College Student Union printer (priority queue)
James complained that the student union printer does not comply with the FIFO principle. Many of the students who printed the printer later than
Hdu 3345 War Chess (bfs + priority queue)
War Chess
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission (s): 1732 Accepted Submission (s): 416
Problem DescriptionWar chess is hh's favorite game:
In this
Uva11997 (priority queue, merge)
Question:
K arrays, k values for each number;
If one value is added to each array, a total of k ^ k results are available. The first k is a small value and the result is output;
Ideas:
First, we have two arrays.
Expedition
Time Limit: 1000MS
Memory Limit: 65536K
Total Submissions: 8053
Accepted: 2359
DescriptionA group of cows grabbed a truck and ventured on an expedition deep into the jungle.
The kth great numbertimelimit:2000/1000 MS (java/others) memorylimit:65768/65768 K (java/others) 64-bit integer IO forma T:%i64dProblem Descriptionxiao Ming and Xiao Bao is playing a simple Numbers game. In a round Xiao Ming can choose to write down
Time limit:20 Sec Memory limit:552 MBsubmit:2435 solved:1195DescriptionSmall Z is a small famous pianist, recently Dr. C gave a small z a super piano, small z hope to use this piano to create the world's most beautiful music. The super piano can
A-Sign Incrawling in process ... crawling failed time limit:1000MS Memory Limit:65768KB 64bit IO Format:%i64d &%i64u Submit Status Practice HDU 4006DescriptionXiao Ming and Xiao Bao is playing a simple Numbers game. In a round Xiao Ming can
Easy to use priority queue to select the maximum value;But through the analysis, the first removal of the earthworm is still longer than after the division, so you can directly use the monotone queue to find a team head, divided into three monotone
Test instructions: Give K a weight value. A graph containing n points, one-way edges of R bars.Each edge has two weights, one of which is long and the other is an additional weight.Ask for the shortest path if the sum of the additional weights of
TemplateSerie A championship: give you a picture, 1 always root, each party has a single value, each point has the right to re.Price value per edge = SUM (subsequent node weight) * unit Price value.The lowest price requires a tree value, which forms
It should be a priority queue or a pile of questions because each number should be the number that has been obtained, but the 2*7 is greater than the 3*2, it must be guaranteed that every acquisition is not *7 the smallest numberBut it actively
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