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HDU 5093 Battle ships (binary graph matching)

The problem is a classic two-part matching problem. No two boats can be placed on the same column (row) unless an iceberg is separated. For this two-dimensional plan, it is easy to think of dividing the rows and columns into two sets, and then matching the two graphs, and when a row coordinate is matched to a column coordinate, the lattice can place the ship. So in order to make any two ships are not in the same row or the same column, unless there is an iceberg, we can each row in a row can onl

StarCraft II Battle problem

! C + + programs:#include using namespacestd;intMain () {intN; intK; intm; intl; intx; CIN>> n >> k >> l >> m >>x; intMarine =x; intZERG1 =m; intZERG2 =m; intDistance =N; while(Marine >0 (Zerg1 >0|| Zerg2 >0)) { if(Distance zerg1 >0) {Distance--; Zerg1-=l; } Else if(Distance zerg1 0 zerg2 >0) {Distance--; Zerg2-=l; }Else if(Zerg1 >0) {Zerg1-=l; Marine-= k *2; } Else{zerg2-=l; Marine-=K; } } if(Marine >0) cout "Marine win!"Endl; Elsecout "zergling

Codeforces Round #Pi (Div. 2)--d one-dimensional Battle Ships

, because they also have a t in between, so it's equivalent to T1,t2 being split.Then the current number of ships can be obtained by another formula: sum=sum-(T2-T1)/(a+1) + (T-T1)/(a+1) + (T2-T)/(a+1); Here's the equivalent of reducing the part of the original Then add the maximum number of boats that can be accommodated by the interval after separation.When sumHere you find the left and right endpoints with a binary lookup.#include Admire the people who can think out. Wish I can become the sam

A big battle of elective courses

the T Group data is in the following format: line 1 :2 integers,n,m. N indicates the total number of courses and the course number is 1..N. M represents the number of sequential relationships. 1 line 2..m+1 : 2 integers per line, a,b. Indicates that course A is a pre-set course for course B . OutputSection1..Trows: Per line1string, if the group information is correct, the output"Correct", if the group information is incorrect, the output"Wrong". Sample input22 21 22 13 21 21 3Sample outputW

Hdu 5542 The Battle of Chibi (2015ccpc-c question)

-1, B[i]-1);//F[k][i] = sum{f[k-1][x], 1 A if(F[k][i] >= MoD) f[k][i]-=MoD; + } theAdd (k, b[i], f[k][i]);//update the calculated f[k][i] into the tree array - } $Ans + = f[m][i];//this time f[m][i] has been counted, so add to the answer the if(ans >= mod) ans-=MoD; the } theprintf"Case #%d:%i64d\n", ++Case , ans); the } - return 0; in}DP Array record state, and then update into the corresponding data structure, and Hdu

85th: The powerful expressive battle of the for expression in Scala

Today "DT Big Data DreamWorks Video" 85th: The powerful expression of the for expressions in Scala51CTO Video: http://edu.51cto.com/lesson/id-71503.html(DT Big Data Dream factory Scala all videos, PPT and code in Baidu Cloud Disk Link: Http://url.cn/fSFPjS)85 Talk about the power of Scala for expressionsThe behavior of the higher-order function specifies the details of the data processing.Case class Person (name:string,ismale:boolean,children:person*)//children variable parameterObject for_expre

Php_i love u (2) php food and clothing parents: Java and PHP efficiency battle one: Fibonacci sequence

Php_i love u (1) php Food and clothing parents: Java and PHP efficiency battle one: Fibonacci sequence Fibonacci EXPLANATION See: http://zh.wikipedia.org/wiki/%E6%96%90%E6%B3%A2%E9%82%A3%E5%A5%91%E6%95%B0%E5%88%97 (should be 1, Wiki's formula is wrong!?! ) (n?2) This time write the Java code First: Class FB {static int f1b (int x) {if ((0==x) | | | (1==x)) {return 1;}int A;A=F1B (x-1) +x;System.out.println (a);return A;}public static vo

cocos2dx3.2 development RPG "flighting" (vii) back to the battle scene, update the character's stacking order

hero class and M_monsterdeqIn fact, the hero class is a derived class of role, and Monster is also a derived class of role. When it comes to real battles (rather than walking alone), we'll talk about the difference.If your last section has been able to successfully implement the control movement of a character, you may find that there is a serious problem that the z-axis order of role does not change, resulting in the more addchild role. This is clearly not in line with our requirements. Our re

1013. Battle over Cities (25)

nodes connected through that node in DFS are separated. */#include"iostream"#include"CString"using namespacestd;#defineMAX 1001intMap[max][max];intVisited[max];intN, M, K;voidDfsintj) {Visited[j]=1; for(inti =1; I ) { if(!visited[i] map[j][i] = =1) {DFS (i); } }}intMain () {CIN>> n >> M >>K; while(m--) { intA, B; CIN>> a >>b; MAP[A][B]= Map[b][a] =1; } while(k--) { intnum =0; intl; CIN>>l; Memset (visited,0,sizeof(visited)); VISITED[L]=1; for(intI=1; i)

Big God dozen millet, Zhou Hongyi's strategy battle

" strategy for Zhou Hongyi. Through the "free" strategy, Zhou Hongyi played the Great God's fame, played the Big God sign, more users began to use the big God mobile phone. In the case of the great God against millet, the great God has proved himself to be the king of mobile phone price. It can be said that Zhou Hongyi's strategy has been half done. The other half of Zhou's 祎 strategy is his dual-brand strategy. Big God is the knife, responsible for the mobile phone market front-end of the fight

[HDOJ5542] The Battle of Chibi (DP, tree-like array)

); - for(inti =1; I ) { thescanf"%d", a[i]); +h[i-1] =A[i]; A } theSort (h, h+n); hcnt = Unique (h, h+n)-h; + for(inti =1; I 1; -Memset (DP,0,sizeof(DP)); $ for(inti =1; I ) { $ intLo =min (i, m); - for(intj =1; J ) { - if(J = =1) { theUpdate (J, A[i],1); - Continue;Wuyi } the intTMP = SUM (J-1, a[i]-1); - Update (J, A[i], TMP); Wu } - } Aboutprintf"

Use C # to create a "QQ battle platform room dashboard"

annoying Prompt Windows? As a result, the "QQ battle platform room dashboard" in this article was born like this (How many hands can be liberated, everyone applauded ......) 2. How to squeeze a room "? As mentioned above, the "squeeze room" means to help us automatically "squeeze" the room, but how does it help us "squeeze? After all, it is a machine, not a human. It will not automatically "squeeze" us as soon as we see the room, unless we have cu

Achieve efficient battle drift in Unity3d

All rights reserved, reprint must indicate the source!like the fire shadow, like Java, like Unity3d, like game development can join mu ye cun q Group: 379076227This week, some netizens mentioned the use of Ngui to fight blood, take the injury and other text performance is too poor. That's true, I've also found that UIPanel occupies a high CPU on the profile before (on the Android machine NGUI 3.8.2,1000 block).So eventually in the fight floating the text this piece does not use Ngui, but creates

JavaFX battle flag game development Lesson 6 mobile scope acquisition

JavaFX battle flag game development Lesson 6 mobile scope acquisition For a while, I haven't written a tutorial on this banner game Demo. Continue now. In fact, the range acquisition of War flag games is not complex, mainly because of node traversal and weight comparison. As you know, in the * Star shortest path algorithm, the weight value has a g value and an H value, the G value is the movement from the starting point to the current point (usually t

Python implements code sharing for battle against snakes and snakes

Python implements code sharing for battle against snakes and snakes I feel that after the implementation of the new game review policy, the domestic mobile game market is a little deserted. Are all new games waiting for review. In addition to competing for Pokemon Go, the media seems to have heard nothing. It wasn't until recently that several people suddenly talked about the same game, and some people on the internet showed that their moments had be

Programmer's Forever Chicken Blood-the Battle of programming language "silver bullet"

: relationship) {Switch Intimacy {case. Lover:Lovers. Append (Friend)Friends, lovers. Append (self)Case. Familiar with. Face knowledge:Friends. Append (Friend)Friends. Friend. Append (self)}}}Let xiaoming = Man (name: "Xiaoming")Let Little red = Man (name: "Little Red")Xiao Ming. Add relationship (xiaoming, pro density:. Lover)From this program can be seen in Chinese programming is still well understood, but this example also has a problem, here is not all Chinese, not very easy to language, thi

The security of the Android app battle against attack

cracking5, in order to deal with the senior crack small white, we will adopt the application of the reinforcement strategy, the DEX,SO, resource files to strengthen, increase the anti-compilation work and debugging difficultyIv. SummaryThrough this article we see, introduced a number of methods of security protection applications, but we also introduced in each method how the cracker responded to this method, so said here that these security protection can be cracked, just a matter of time, ove

The Battle of Moscow PHP-502 bad Gateway

. If you feel trouble, you can encapsulate the following code as a function yourself.Of course, the reason that causes the php-cgi process CPU 100% is not the only one, then, how to determine the file_get_contents () function is caused?First, open PHP New PHP-FPM want to go to the file format is:Slowlog=/tmp/slow.logRequest_slowlog_timeout=3sThe number of code lines that are slow to execute is printed in the log.  First, use the top command to see the php-cgi process with high CPU usage.Find the

Old boy's 2017-year Shell programming battle book cover design You're the Boss!

Dear friends, everyone, the old boy's second book, "Shell Programming Combat" is about to meet with everyone (expected early January 2017)!Please participate in the selection of the color of the cover, loudly tell the old boy, time until December 22 22:00, your choice will directly determine the book's cover design, thank you!Please comment out the book like 1, blue or 2, Orange! can also add reason!we can also focus on new book publishing Time trends, operation and maintenanceQGroup384467551Arc

The beginning of the battle--spring

Spring is a Java open source framework created to address the complexities of enterprise application development. Here are some of the notes I summarized in my study process:How to learn Spring -mastering usage-in-depth understanding-repeated summing-in-depth understanding and practiceSpring Resource document: http://spring.io/http://projects.spring.io/spring-framework/1. Importing the JAR Package    Each core simply imports its bytecode.2. Target class3. Configuration filesConfigure ServiceUni

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