braintree result object

If it is the client's Http+json interface project, the use of Jersery framework development is absolutely the first choice without JSP and other view views. In the architecture based on SPRING3 MVC, the return type of Http+json is also well supported. However, in the development work, the upgrade of the function is based on the established architecture is very common situation. I encountered the need to develop a Struts2 based Http+json return type interface is based on the established framework

Note: Use the object name when you use the Strtus-json-plugin serialization object property to configure the Includeproperties property under the result label. * or specify a property name in such a way that the object property name cannot be written.Problem:There are two properties in action: String

$ Mysqlinewmysqli ( quot; 127.0.0.1 quot;, quot; root quot;, quot;, quot; test quot ;);...... $ res $ mysqli- gt; query ($ query); $ row_cnt $ res- gt; num_rows; number of records in the result set ...... is $ res an object? Why? (I always thought that all objects are... $ mysqli = new mysqli ("127.0.0.1", "root", "", "test "); ...... $ Res = $ mysqli-> query ($ query ); $ Row_cnt = $ res-> num_rows;

When designing our own functions, in addition to using the ref or out parameters, it is difficult to return multiple results,We often want to know whether the operation is successful and provide a prompt, or return a value such as dataset and arraylist.Therefore, a result object is created:It contains three child objects,A bool type is used to record whether the operation is successful;A string used to reco

public class resultutil{public static Result Success (Object object) {Result result = new result ();Result.setcode (0);Result.setmsg ("Success");Result.setdata (object);return

New Person classSubclass of Person StudentTeacherToday I think of the database encapsulation, because the query results are inherited from Nsmanagerobject, but his sub-class properties are not necessarily the same, so I think I can not judge after the query that he is the subclass and according to the properties of the subclass to assign values, So first I want the class of the object to be stored in the array to judgeThe test is as follows: (the main

Import tf56.sofa. serializer. jsongenerateutil;/*** returned object result encapsulation * @ athor changmeng. liu * @ date 2014-7-25 * @ version 1.0 * @ update */public class result {final string success = "success"; final string error = "error "; private string COUNT = "";/** response data */private object data;/** re

You can use the nextresult method of the datareader object to retrieve the next result set. If the return value of this method is false, it indicates that the last result set has been reached. For example: Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--> Public Void Page_load (

Duplicate definitions may result in an error in setting the object reference to an instance.Author: icech Generally, in C #, the error "the instance where the object is not referenced" is that the control name does not correspond to that in codebehind. For Beginners, repeated definitions in encoding can also cause this problem. The following is an example: Using

Error: Org.springframework.jdbc.UncategorizedSQLException:SqlMapClient operation; Uncategorized SQLException for SQL []; SQL state [NULL]; Error code [0]; ---The error occurred in Com/sinosoft/para/conf/a_t_4_sqlmap.xml. ---The error occurred while applying a result map. ---Check the a_t_4.a_t_4result. ---The error happened while setting a property on the result objec