stanford algorithms coursera

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Coursera open course notes: "Advice for applying machine learning", 10 class of machine learning at Stanford University )"

Stanford University machine Learning lesson 10 "Neural Networks: Learning" study notes. This course consists of seven parts: 1) Deciding what to try next (decide what to do next) 2) Evaluating a hypothesis (Evaluation hypothesis) 3) Model selection and training/validation/test sets (Model selection and training/verification/test Set) 4) Diagnosing bias vs. variance (diagnostic deviation and variance) 5) Regularization and bias/variance (Regularization

[Original] Andrew Ng chose to fill in the blanks in Coursera for Stanford machine learning.

Week 2 gradient descent for multiple variables [1] multi-variable linear model cost function Answer: AB [2] feature scaling feature Scaling Answer: d 【] Answer: 【] Answer: 【] Answer: 【] Answer: 【] Answer: 【] Answer: 【] Answer: 【] Answer: 【] Answer: 【] Answer: 【] Answer: 【] Answer: 【] Answer: 【] Answer: 【] Answer: [Original] Andrew Ng chose to fill in the blanks in Coursera for Sta

Stanford Algorithms (a): Multiply by large number (C + +)

Stanford Algorithms (a): Multiply by large number (C + +)Just not in the Chinese university Mooc attended the course of Chen teacher 数据结构 , Harvest very big. Feel the strike, also put the algorithm part also to a school, on the Coursera registered a Stanford University algorithm class, the amount of the course is very

Coursera algorithms week2 Basic sort interview Questions:1 intersection of the sets

Original title:Given Arrays a[] and b[], each containing n distinct 2D points in the plane, design a subquadratic algorithm to count The number of points that is contained both in array a[] and array b[].The goal of the topic is to calculate the number of duplicate point, very simple, the code is as follows1 ImportJava.awt.Point;2 Importjava.util.Arrays;3 ImportJava.util.HashSet;4 ImportJava.util.Set;5 6 ImportEdu.princeton.cs.algs4.StdRandom;7 8 Public classplanepoints {9 PrivatesetNewHash

Coursera Algorithms week3 Merge sort exercise quiz 1:merging with smaller auxiliary array

]; - } - System.out.println (arrays.tostring (aux)); the intL = 0; - intR =N; - for(intk = 0; k){ - if(l >= N) Break;//The array of auxiliary elements is exhausted, and the right side of the array does not need to be shifted. + Else if(R>=2*n) array[k]=aux[l++];//all elements of the right element of array are placed in the appropriate position, then simply move the elements of the auxiliary array to the right of the array - Els

Coursera algorithms Week3 Quick Sort Exercise quiz: Selection in two sorted arrays (looking for the K-element from both ordered arrays)

} - to Public Static voidMain (string[] args) { + intn = 10; - intN1 =stdrandom.uniform (n); the intN2 = nN1; * int[] A =New int[N1]; $ int[] B =New int[N2];Panax Notoginseng for(inti=0;i){ -A[i] = stdrandom.uniform (100); the } + for(inti=0;i){ AB[i] = stdrandom.uniform (100); the } + Arrays.sort (a); - Arrays.sort (b); $System.out.println ("a=" +arrays.tostring (a)); $System.out.println ("b=" +arrays.tostr

(note) Stanford machine Learning--generating learning algorithms

two classification problem, so the model is modeled as Bernoulli distributionIn the case of a given Y, naive Bayes assumes that each word appears to be independent of each other, and that each word appears to be a two classification problem, that is, it is also modeled as a Bernoulli distribution.In the GDA model, it is assumed that we are still dealing with a two classification problem, and that the models are still modeled as Bernoulli distributions.In the case of a given y, the value of x is

Machine Learning-Stanford: Learning Note 5-generating learning algorithms

unreasonable. That is, in the past two months the word has not appeared in the mail, it is considered that the probability of 0, unreasonable.Generally speaking, it is unreasonable to think that these events will not happen if they have not been seen before . Solve this problem with Laplace smoothing.4. Laplace SmoothingAccording to the maximum likelihood estimate, p (y=1) = # "1" s/(# "0" s + # "1" s), that is, the probability of Y being 1 is the ratio of the number of 1 in the sample to all s

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