subnetting exam

Read Catalogue I. IP Address Basics 1.1 IP Address structure and classification 1.2 special IP address 1.3 subnet mask 1.4 IP address request two. subnetting 2.1 subnetting Concept 2.2 Class C sub-network Division 2.3 subnetting Step 2.4 subnetting Case 2.5 sub-division Network considerations 2.6 Why

IP addresses are classified into five categories--------------------------------------------------------------------------------------------------------------- ----------------------------------------------------the meaning of the subnet mask and subnetting according to the subnet maskThe subnet mask is used to divide subnets. For example, a Class A network can hold 16777214 hosts. However, in practice, it is impossible to use a class A network only f

addresses: "192.168.5.253/30, 192.168.5.254/30"Broadcast address: "192.168.5.255/30"quickly divide subnets to determine IPLet's take example 2 for example:The topic requires that we divide the 192.168.5.0/24 network address into subnets that can accommodate 101/54/2 hosts. Therefore, we need to determine the host location, and then determine the network bit based on the host bit, and finally determine the detailed IP address.① determining the host bitSet the number of hosts that you need to be

LAN.WANThe last network segment is a WAN connection and requires 2 host addresses. Support WAN links with just 2 primary seats. 2^2-2 = 2.This leaves 8 bits to define the local subnet address. The next available address block is 172.16.2.192/30.Address: 172.16.2.192Binary representation:10101100.00010000.0000010.11000000Mask: 255.255.255.252Represents 30 bits in binary:11111111.11111111.1111111.11111100The IPV4 host address range provided is:172.16.2.193 to 172.16.2.194, broadcast address is 17

11111111Example of subnetting:1, a company to apply to a class C IP address, but to connect 6 subsidiaries, the largest one sub-The company has 26 computers, each subsidiary in a network segment, the subnet mask should be set to?A: Assume that the C network address is 192.168.0.0/24,6 subsidiary, namely Divide 8 subnets, two not, each subnet can hold 30 IP192.168.0.0-192.168.0.31/27-255.255.255.224192.168.0.32-192.168.0.63/27-255.255.255.224192.168.0

application, a company applied for a public network, such as 201.1.2.0/24, but the company has two groups, a group of the number of hosts is 6, the number of hosts in the other group is 4, and do not want the two groups of hosts to communicate with each other, if you apply for a public network , the cost is too high, so it is necessary to divide this network into multiple subnets. The subnet is divided by the first m bits in the host bit in the network address and the network address bits as th

mask calculation. Network ID Results We all know that the network ID part is unchanged, the host ID portion becomes 0, then in the calculation of the network ID, first look at how many bits in the subnet mask to represent the network, corresponding to the IP address conversion to binary only the previous few, such as 192.168.176.15/ 19, the network ID altogether 19 bits, then the network ID the first two bytes is 192.168.x.0 to change the third byte. So how do you quickly calculate the value o

subnets will need to occupy 1 bits of the original host identity bit. At this point the network number bit becomes 22 bits and the host label becomes 7 bits. Similarly borrowing 2 host bits can divide a class C network into 4 subnets ... How did the computer know if the network was divided into subnets? This can be seen from the subnet mask. The subnet mask is as 32bit as the IP address, and the subnet mask is determined by using "1" for all corresponding bits that identify the network number i

First, a sample from a Shehiren teacher's book is referenced:Host H1 the process of sending packets to H2:First, with the subnet mask in the subnet:255.255.255.128 and target host H2 IP address:128.30.33.128 and get network number: 128.30.33.128. Obviously this does not match the network number of Subnet 1:128.30.33.0.The datagram is then forwarded by the default route R1 Subnet 1. At this point, R1 will look for its own routing table. Think of the host address and subnet mask of the H2, and whe

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1. The array name is a pointer constant representing the first address of the array space, and the constant assignment is not allowed in the program.such as int a[]; A is the array name, which represents the pointer constant of the first address of the array controlA = 0; is wrong and does not allow assigning values to pointer constants2. You can point to a constant by the pointer, but you cannot modify the contents of the constant through the pointersuch as: Char *p;p = "Testing"*p = ' 0 ';3.So

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?? I also want to ask why:6 7 array size Others len++ less than themselves with one8 9 */Ten#include One#include A#include -#include - #defineINF 2147483647 the using namespacestd; - intbit[ -]; - Long Longdp[ -][ -][2005]; - Long LongRead () { + CharCintf=1;Long Longx=0; c=GetChar (); - while(c>'9'|| c'0'){if(c=='-') f=-1; c=GetChar ();} + while(c'9'c>='0') x=x*Ten+c-'0', c=GetChar (); A returnf*x; at } - - Long LongDfsintPosintOintSumintlimit) { - if(pos==0)returnsum

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Another Alibaba pen exam and another Alibaba exam The next written examination... Various busy times... 1. If the key code K of an integer is hashed to a hash list with N slots, which of the following hash functions are good hash functions () A. h (k) = K/n B. h (k) = 1 C. h (k) = k mod N D. h (k) = (K + random (N) mod N, random (N) returns an integer ranging from 0 to N. 2. In the following sorting algorit

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17. Software evaluation development and evaluator 17.1 the work principle of the surveyorFor software testers, the tasks and objectives are as follows:(1) The basic goal of software testers is to find bugs, which is the first condition for testing.(2) The purpose of software testing is to verify requirements, software Requirements specification is the basis of software testing(3) Software testers must ensure that the identified bugs are closed(4) Software testers should make an objective evaluat