bubble sort visualization

Exchange Sort : 22 The key code for the sorted record, in reverse order, is exchanged until there is no reverse order.The simplest sort of swap is: bubble sort.Bubble Sort (Bubble sort, also known as

Bubble sort is a sort of algorithm that we basically get into contact with in the beginning of programming, since it is more concise and more image.Its idea is to let each of the adjacent elements compare, if they do not follow the ascending or descending, then exchange their positions, repeat the operation, the largest or smallest elements like bubbles, rise to

Packagecom.sort.test;Importjava.util.Arrays;ImportJava.util.Random; Public classVeriablesort {Private Static intmax_number=10; Public Static voidMain (string[] args) {//TODO auto-generated Method Stub int[] Array =New int[Max_number]; Random Rand=NewRandom (); for(inti = 0; i ) {Array[i]= Rand.nextint (20); } //the original array sequenceSystem.out.println ("The original array is sorted as follows:"); System.out.println (arrays.tostring (array));//Bubblesort (array);System.out.pr

Bubble sort Privatevoid Swap (Int[] arrays,int I,Int J) {int temp; temp = arrays[i]; Arrays[i] = Arrays[j]; arrays[j] = temp;} public int[] Arrayintsort (int[] array) {for (int i = 1; i ARRAY.LENGTH; i++) {for (int j = 0; J array.length-i; J + +) {if (array[j] > array[j + 1]) {swap (array, J, j + 1);}} return array;}

Text descriptionFirst the first record's keyword and the second record's keyword are compared, if in reverse order (L.r[1].key>l.r[2].key), two records are exchanged for the location, and then the second record and the third record's keywords are compared. And so on, until the n-1 record and the nth record have been compared by a keyword. The process described above is called the first bubbling sort, and the result is that the largest record of the ke

] = 0; } index = 0; } Bubble sort: Countdown from the last index Public void Bubblesort () { int temp; Traverse forward from the largest index until the index is 1 for (int i = upper; I >= 1; i--) { Iterate backward from the smallest index until the current element for (int j = 0; J

Bubble sort (Bubble sort) is a simple sort algorithm. It repeatedly visited the sequence to sort, comparing two elements at a time, and swapping them out if they were wrong in the order. The work of the sequence of visits is repea

650) this.width=650; "src=" Http://img.baidu.com/hi/jx2/j_0057.gif "alt=" j_0057.gif "/> bubble sort: (e.g. ascending)In the first order, starting with the first element, the entire sequence of elements to be sorted is scanned, and if the adjacent two elements are reversed, the position is swapped. Until the last element, at this point, the last element must be the largest element.The second order is still

Problem Solving steps: Use a For Loop (outer loop) to specify the number of laps to loop (by illustration, the number of laps in an array loop is 1) In each lap, a for loop (inner Loop) completes the adjacent element values in order to compare the large values to the subsequent elements The number of cycles per circle is determined by the cycle of the first circle. As shown A) the number of inner loops is an array length-1 when the first loop element is comparedb) in the se

Package com.java.base.sort.algorithm;/** * Bubble Sort * * Execution Result:冒泡排序前：9,8,11,17,12,2,4,5,20,3,1,冒泡排序后：1,2,3,4,5,8,9,11,12,17,20,Sort algorithm--bubble sort

Reprint please indicate the source, thank you!Bubble Sorting algorithm idea: Scan the record sequence from bottom to top (or up and down), and the adjacent two records Ri Ri－1 are swapped with (or Ri+1 ) if in reverse order. Exchange Sort Bubble sort Quick

Basic ideas22 The comparison between adjacent elements, if the former is greater than the latter, then the Exchange ;Set the array length to n.1. Compare the next two data, if the previous data is larger than the data, two data will be exchanged.2. So that the No. 0 data of the array to N-1 data after one traversal, the largest one of the data is "sink" to the N-1 position of the array.3. N=n-1, if N is not 0, repeat the previous two steps, otherwise the sor